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In the fraction x/y, where x and y are positive integers, what is the

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In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6
(2) x = 1

OPEN DISCUSSION OF THIS QUESTION IS HERE: http://gmatclub.com/forum/in-the-fracti ... 68099.html
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In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6 --> LCM of \(y\) and 3 is is 6 --> \(y=2\) or \(y=6\) (the least common denominator of \(\frac{x}{2}\) and \(\frac{1}{3}\) is 6 and the least common denominator of \(\frac{x}{6}\) and \(\frac{1}{3}\) is also 6). Not sufficient.

(2) \(x=1\) --> no info about \(y\). Not sufficient.

(1)+(2) \(y\) still can be 2 or 6. Not sufficient.

Answer: E.
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In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6
(2) x=1

For me the answer is C.

Statement 1 is clearly insufficient because x can take any value. Value of y has to be 6 though for LCD to be 6.

Statement 2 gives us the value of x.

Combining the two the value of y should be 6. Am I right?
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Last edited by Bunuel on 09 Dec 2017, 03:59, edited 3 times in total.
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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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New post 29 Jan 2012, 16:08
enigma123 wrote:
In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6
(2) x=1

For me the answer is C.

Statement 1 is clearly insufficient because x can take any value. Value of y has to be 6 though for LCD to be 6.

Statement 2 gives us the value of x.

Combining the two the value of y should be 6. Am I right?


I don't quite follow your logic. If you thought that, from Statement 1 alone, you could be certain that y = 6, you should have selected the answer A, since the question asks for the value of y. It doesn't ask for the value of x.

The answer is not A, however, since using both statements, x/y could be equal to 1/2 or it could be equal to 1/6, so y could be 2 or 6, and the answer is E.
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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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New post 29 Jan 2012, 20:33
enigma123 wrote:
In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6
(2) x=1

For me the answer is C.

Statement 1 is clearly insufficient because x can take any value. Value of y has to be 6 though for LCD to be 6.

Statement 2 gives us the value of x.

Combining the two the value of y should be 6. Am I right?


I could not get the question here... does here the statement least common denominator of x/y and 1/3 means lcm(x,y)/hcf(x,y) (if f1 = num1/den1 and f2 = num2/den2 are both fractions in their simplest form, then LCM(f1,f2) = LCM(num1.num2)/GCD(den1,den2)).

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enigma123 wrote:
In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6
(2) x=1

For me the answer is C.

Statement 1 is clearly insufficient because x can take any value. Value of y has to be 6 though for LCD to be 6.

Statement 2 gives us the value of x.

Combining the two the value of y should be 6. Am I right?


I could not get the question here... does here the statement least common denominator of x/y and 1/3 means lcm(x,y)/hcf(x,y) (if f1 = num1/den1 and f2 = num2/den2 are both fractions in their simplest form, then LCM(f1,f2) = LCM(num1.num2)/GCD(den1,den2)).


The least common denominator of x/y and 1/3 is 6 means the least common multiple of y and 3 is 6.

Hope it's clear.
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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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New post 20 Sep 2012, 06:10
Bunuel wrote:
metallicafan wrote:
In the fraction \(x/y\) , where x and y are positive integers, what is the value of y?

(1) The least common denominator of \(x/y\) and \(1/3\)is 6.
(2) x = 1


In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6 --> LCM of \(y\) and 3 is is 6 --> \(y=2\) or \(y=6\) (the least common denominator of \(\frac{x}{2}\) and \(\frac{1}{3}\) is 6 and the least common denominator of \(\frac{x}{6}\) and \(\frac{1}{3}\) is also 6). Not sufficient.

(2) \(x=1\) --> no info about \(y\). Not sufficient.

(1)+(2) \(y\) still can be 2 or 6. Not sufficient.

Answer: E.



Hi Bunuel,

This time i am not able to understand the explanation given by you.
Assuming x=1 & y can be either 2 or 6, I want to know how come the LCM of (1/2 , 1/3) & (1/6, 1/3) can be 6. As per me the LCM has to be 1 & 1/3 respectively.

Kindly enlighten me.
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New post 20 Sep 2012, 06:47
fameatop wrote:
Bunuel wrote:
metallicafan wrote:
In the fraction \(x/y\) , where x and y are positive integers, what is the value of y?

(1) The least common denominator of \(x/y\) and \(1/3\)is 6.
(2) x = 1


In the fraction x/y, where x and y are positive integers, what is the value of y?

(1) The least common denominator of x/y and 1/3 is 6 --> LCM of \(y\) and 3 is is 6 --> \(y=2\) or \(y=6\) (the least common denominator of \(\frac{x}{2}\) and \(\frac{1}{3}\) is 6 and the least common denominator of \(\frac{x}{6}\) and \(\frac{1}{3}\) is also 6). Not sufficient.

(2) \(x=1\) --> no info about \(y\). Not sufficient.

(1)+(2) \(y\) still can be 2 or 6. Not sufficient.

Answer: E.



Hi Bunuel,

This time i am not able to understand the explanation given by you.
Assuming x=1 & y can be either 2 or 6, I want to know how come the LCM of (1/2 , 1/3) & (1/6, 1/3) can be 6. As per me the LCM has to be 1 & 1/3 respectively.

Kindly enlighten me.
Waiting for reply


We are told that "The least common denominator of x/y and 1/3 is 6" not LCM of 1/2 and 1/3.
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New post 20 Sep 2012, 07:38
Hi Bunuel,
Ok, Forget the question. Can you tell me what is the LCM of (1/2 , 1/3) & (1/6, 1/3) or how to calculate the LCM of two fractions.
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New post 20 Sep 2012, 07:43
fameatop wrote:
Hi Bunuel,
Ok, Forget the question. Can you tell me what is the LCM of (1/2 , 1/3) & (1/6, 1/3) or how to calculate the LCM of two fractions.


The least common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.
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New post 22 Dec 2012, 21:54
Bunuel,

how to find the LCM and GCD of fractions?
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New post 23 Dec 2012, 04:48
Sachin9 wrote:
Bunuel,

how to find the LCM and GCD of fractions?


You don't need this for the GMAT.

Every GMAT divisibility question will tell you in advance that any unknowns represent positive integers, which means that ALL GMAT divisibility questions (including questions on LCM and GCD) are limited to positive integers only.
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New post 23 Dec 2012, 08:53
So how did you derive the following?

The least common denominator of x/y and 1/3 is 6 --> LCM of y and 3 is is 6
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Bunuel wrote:
Sachin9 wrote:
So how did you derive the following?

The least common denominator of x/y and 1/3 is 6 --> LCM of y and 3 is is 6


The least common denominator of x/y and 1/3 is 6 --> the least common multiple of y and 3 is is 6.


I am still not understanding how you derived the following :
The least common denominator of x/y and 1/3 is 6 --> the least common multiple of y and 3 is is 6.

Please elaborate..
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New post 04 Jan 2013, 04:34
Sachin9 wrote:
Bunuel wrote:
Sachin9 wrote:
So how did you derive the following?

The least common denominator of x/y and 1/3 is 6 --> LCM of y and 3 is is 6


The least common denominator of x/y and 1/3 is 6 --> the least common multiple of y and 3 is is 6.


I am still not understanding how you derived the following :
The least common denominator of x/y and 1/3 is 6 --> the least common multiple of y and 3 is is 6.

Please elaborate..


Not sure how to elaborate this further.

We are told that the least common denominator of x/y and 1/3 is 6. The denominators of these fractions are y and 3, so we are basically told that the least common multiple of y and 3 is 6.

It's quite straightforward.
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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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New post 04 Jan 2013, 04:56
Bunuel wrote:
Not sure how to elaborate this further.

We are told that the least common denominator of x/y and 1/3 is 6. The denominators of these fractions are y and 3, so we are basically told that the least common multiple of y and 3 is 6.

It's quite straightforward.


I am new here, but I will try to explain my way of thinking. Sorry if I get some terms wrong, English is not my primary language.

Remember the way to add up 2 fractions with different denominators: you should look for the smallest (least) common denominators (and muliply the nominators).

x/y + p/q = (x*q + p*y)/(y*p)

Also you would show y and p in factors (prefferaby prime numbers) to find the least denominator, but because 3 is a prime number and den(y*3) = 6 = 3*2 you can skip this step.

The rest of the question is explained :) Y can be 2 or 6...

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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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Sachin9 wrote:
Bunuel wrote:
Sachin9 wrote:
So how did you derive the following?

The least common denominator of x/y and 1/3 is 6 --> LCM of y and 3 is is 6


The least common denominator of x/y and 1/3 is 6 --> the least common multiple of y and 3 is is 6.


I am still not understanding how you derived the following :
The least common denominator of x/y and 1/3 is 6 --> the least common multiple of y and 3 is is 6.

Please elaborate..


Responding to a pm:

It's pretty simple really and I don't know what to add to Bunuel's post.

Are you comfortable working with fractions? If yes, what do you do to add two fractions say 1/2 and 1/3? First, you give them a common denominator (6 in this case). Why 6? Because it is a common multiple of 2 and 3.
Similarly, what if the two fractions are 1/4 and 1/6? What common denominator will you take? You can take the LCM of 4 and 6 which is 12 or you can even multiply 4 and 6 to get 24.
1/4 + 1/6 = 3/12 + 2/12 = 5/12
or
1/4 + 1/6 = 6/24 + 4/24 = 10/24 = 5/12

If you need to find the LOWEST common denominator, it will be the LCM. So in the question above, the least common denominator of x/y and 1/3 is 6 implies that the least common multiple of y and 3 is 6.
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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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New post 21 Jan 2013, 23:14
1. LCD of x/y and 1/3 is 6

LCD(3,2) = 6
LCD(3,6) = 6

y could be 2 or 6.
INSUFFICIENT.

2. x = 1 ... This doesn't give us anything much. x/y could be 1/7 or 1/8
INSUFFICIENT.

Together: 1/y and 1/3 has an LCD of 6
LCD(1/2,1/3) is 6
LCD(1/6,1/3) is 6

INSUFFICIENT.

Answer: E
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Re: In the fraction x/y, where x and y are positive integers, what is the [#permalink]

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nikhilsrl wrote:
In the fraction x/y, where x and y are positive integers, what is the value of y?

1) The least common denominator of x/y and 1/3 is 6?
2) x = 1

OA is provided

[Reveal] Spoiler:
I chose A thinking y needs to be 6. Not sure what is wrong there.


OPEN DISCUSSION OF THIS QUESTION IS HERE: in-the-fraction-x-y-where-x-and-y-are-positive-integers-wh-168099.html


In the fraction x/y, where x and y are positive integers, what is the value of y ?

(1) The least common denominator of x/y and 1/3 is 6 --> LCM of y and 3 is is 6 --> y=2 or y=6. Not sufficient.

(2) x = 1 --> no info about y. Not sufficient.

(1)+(2) y can still be 2 or 6. Not sufficient.

Answer: E.

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-the-fraction-x-y-where-x-and-y-are-positive-integers-wh-168099.html
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