EgmatQuantExpert wrote:

In the given diagram, the circle touches the y-axis at the point K whose coordinate is \((0,7)\). If the area of triangle CKO is \(21\) \(units^2\), where C is the center of the circle, find the area of the circle.

A. \(16π\)

B. \(21π\)

C. \(24π\)

D. \(36π\)

E. \(49π\)

Please refer the below attached fig.

As a tangent always makes 90 Deg with centre.

thus the triangle has height = 7 and base =radius = x (let)

given area=21units^2

area = 1/2*base *height

1/2*7*x=21

x=6

thus area of circle = pi* radius^2

= pi*6^2

36π

Ans D

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