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# In the list above, if n is an integer between 1 and 10, inclusive, the

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Math Expert
Joined: 02 Sep 2009
Posts: 50572
In the list above, if n is an integer between 1 and 10, inclusive, the  [#permalink]

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16 Sep 2018, 21:28
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Difficulty:

5% (low)

Question Stats:

95% (01:19) correct 5% (00:58) wrong based on 41 sessions

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2 4 6 8 n 3 5 7 9

In the list above, if n is an integer between 1 and 10, inclusive, then the median must be

A. 4 or 5
B. 5 or 6
C. 6 or 7
E. n
E. 5.5

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Senior Manager
Joined: 18 Jul 2018
Posts: 377
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: In the list above, if n is an integer between 1 and 10, inclusive, the  [#permalink]

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16 Sep 2018, 21:36
2+4+6+8+3+5+7+9+n = 44+n

If n is 1 then median is 45/9 = 5

If n is 10 then median is 54/9 = 6

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Joined: 22 May 2016
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In the list above, if n is an integer between 1 and 10, inclusive, the  [#permalink]

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16 Sep 2018, 22:02
2
Afc0892 wrote:
2+4+6+8+3+5+7+9+n = 44+n

If n is 1 then median is 45/9 = 5

If n is 10 then median is 54/9 = 6

Afc0892
Your method is perfect if n must equal 1 OR 10, because then the integers are consecutive and median = mean.

But median $$\neq$$ mean if n = 2,3,4,5,6,7,8, or 9
n is an integer between 1 and 10, inclusive.

If n = 2, mean = $$\frac{46}{9}=5.1111$$
If n = 7, mean = $$\frac{51}{9}= 5.67$$

Just an issue with the method (absent a mention of extremes and why they work)
Senior Manager
Joined: 18 Jul 2018
Posts: 377
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: In the list above, if n is an integer between 1 and 10, inclusive, the  [#permalink]

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16 Sep 2018, 22:05
generis wrote:
Afc0892 wrote:
2+4+6+8+3+5+7+9+n = 44+n

If n is 1 then median is 45/9 = 5

If n is 10 then median is 54/9 = 6

Afc0892
Your method is perfect if n must equal 1 OR 10, because then the integers are consecutive and median = mean.

But median $$\neq$$ mean if n = 2,3,4,5,6,7,8, or 9
n is an integer between 1 and 10, inclusive.

If n = 2, mean = $$\frac{46}{9}=5.1111$$
If n = 7, mean = $$\frac{51}{9}= 5.67$$

Just an issue with the method (absent a mention of extremes and why they work)

Got it. Thanks
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When you want something, the whole universe conspires in helping you achieve it.

Re: In the list above, if n is an integer between 1 and 10, inclusive, the &nbs [#permalink] 16 Sep 2018, 22:05
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# In the list above, if n is an integer between 1 and 10, inclusive, the

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