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# In the rectangular coordinate system, what is the distance between (−4

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Joined: 02 Sep 2009
Posts: 53657
In the rectangular coordinate system, what is the distance between (−4  [#permalink]

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25 Feb 2019, 02:32
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Difficulty:

15% (low)

Question Stats:

100% (00:59) correct 0% (00:00) wrong based on 16 sessions

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In the rectangular coordinate system, what is the distance between (−4, 3) and (6, −2)?

A. $$5\sqrt{2}$$
B. $$5\sqrt{5}$$
C. $$6\sqrt{3}$$
D. $$6\sqrt{5}$$
E. $$7\sqrt{2}$$

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Re: In the rectangular coordinate system, what is the distance between (−4  [#permalink]

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25 Feb 2019, 04:31
1
Bunuel wrote:
In the rectangular coordinate system, what is the distance between (−4, 3) and (6, −2)?

A. $$5\sqrt{2}$$
B. $$5\sqrt{5}$$
C. $$6\sqrt{3}$$
D. $$6\sqrt{5}$$
E. $$7\sqrt{2}$$

use distance formilw
√(x2-x1)^2+(y2-y1)^2
we get
$$5\sqrt{5}$$
IMO B
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Re: In the rectangular coordinate system, what is the distance between (−4  [#permalink]

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03 Mar 2019, 19:51
Bunuel wrote:
In the rectangular coordinate system, what is the distance between (−4, 3) and (6, −2)?

A. $$5\sqrt{2}$$
B. $$5\sqrt{5}$$
C. $$6\sqrt{3}$$
D. $$6\sqrt{5}$$
E. $$7\sqrt{2}$$

Using the distance formula, we have:

Distance = √[(6 - (-4))^2 + (-2 - 3)^2]

Distance = √[(10)^2 + (-5)^2]

Distance = √125

Distance = √25 x √5

Distance = 5√5

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Re: In the rectangular coordinate system, what is the distance between (−4   [#permalink] 03 Mar 2019, 19:51
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