Hi cosmicomet,This is a genuinely sharp DS instinct. You're right that the algebra in zhanbo's solution quietly
divides by `r^11`, and dividing by something that could be zero is exactly the kind of move worth challenging. So credit where it's due.
Here's why it still lands on
B, though.
Does `r = 0` even fit? Plug it in: the
12th term would be `7 · 0^11 = 0`, and the
15th term `7 · 0^14 = 0`. Then "15th =
64 × 12th" reads `0 = 64 · 0` - technically true. So
mathematically `r = 0` does satisfy the equation.
Why we don't count it. The sequence is built by multiplying by a
constant ratio `r` - that's a geometric sequence, and by standard convention its ratio is
nonzero. If `r = 0`, the sequence collapses to `7, 0, 0, 0, ...` and there's no real "ratio" left to speak of; the relationships become degenerate `0 = 0` identities that hold for
any multiplier. The GMAT treats that as outside the intended setup.
So once `r = 0` is off the table:
- Statement (
1): `r^2 = 16` → `r = 4`
or `r = -4` →
not sufficient.
- Statement (
2): `r^3 = 64` → `r = 4` only (one real cube root) →
sufficient.
That leaves
B. Keep that zero-check habit, though - most DS questions reward it; this one just defines it away.
Answer: B