3vyv
vyvz
----
cbcd
and z = v+3, y = v-3.
(3*1000 + v*100 + y*10 + v) + (v*1000 + y*100 + v*10 + z) = c*1000 + b*100 + c*10 + d
(3000 + 101v + 10y) + (1010v + 100y + z) = 1010c + 100b + d
(3000 + 101v + 10(v - 3)) + (1010v + 100(v - 3) + v + 3) = 1010c + 100b + d
(2970 + 111v) + (1111v - 297) = 1010c + 100b + d
2673 + 1222v = 1010c + 100b + d
- v cannot be 0, 1, 2 cause y will be negative, v cannot be 7, 8, 9 cause z will be two digits
b < c, information is not needed and not helpful since v can only be digits from 3 to 6
v = 3
3 v y v => 3 3 0 3
v y v z => 3 0 3 6
-------------------
= 6 3 3 9, 6 =/= 3, does not suit cbcd.
v = 4
3 v y v => 3 4 1 4
v y v z => 4 1 4 7
-------------------
= 7 5 6 1, 7 =/= 6, does not suit cbcd.
z > 7, z = 8 or 9 since it's a digit problem
If z = 8, v = 5, y = 2
3 v y v => 3 5 2 5
v y v z => 5 2 5 8
-------------------
= 8 7 8 3, c = 8, suits cbcd, yet c = z.
If z = 9, v = 6, y = 3
3 v y v => 3 6 3 6
v y v z => 6 3 6 9
-------------------
= 1 0 0 0 5, does not work since there's one more digit involved.
What choices do you make if the problem itself is solve-able without either statements -.-?
D or E?