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17 Oct 2005, 07:48
Kudos
Bookmarks
In the xy plane , point (r,s) lies on the circle with center at the origin. What is the value of r^2 + s^2.
1) the circle has the radius 2.
2) The point (v2, -v2) lies on the circle.
1) the circle has the radius 2.
2) The point (v2, -v2) lies on the circle.
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17 Oct 2005, 08:12
Kudos
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Answer is: A
The point lies on the circle. Hence a straight drawn up/down (or) left or right would interesect x or y axis. A straight line drawn from (r,s) to origin would then form a triangle (right angled triangle).
Given the above, r^2 + s^2 = hypotenuse^2 (here hypotenuse is nothing but radius)
= 2^2
= 4
Stmt#2. V2 is unknown, hence insufficient (Am I missing anything here?)
Whats OA?
The point lies on the circle. Hence a straight drawn up/down (or) left or right would interesect x or y axis. A straight line drawn from (r,s) to origin would then form a triangle (right angled triangle).
Given the above, r^2 + s^2 = hypotenuse^2 (here hypotenuse is nothing but radius)
= 2^2
= 4
Stmt#2. V2 is unknown, hence insufficient (Am I missing anything here?)
Whats OA?
17 Oct 2005, 09:11
Kudos
Bookmarks
I think there was a mistake. I've already seen this post and this problem.
Statement 2 is different from this stem :
(2) The point (square root(2), -square root(2)) lies on the circle.
OA is D
1st statement -> sudhagar explained it well. Check it.
2nd statement -> you can find the radius because you get the radius from it
Statement 2 is different from this stem :
(2) The point (square root(2), -square root(2)) lies on the circle.
OA is D
1st statement -> sudhagar explained it well. Check it.
2nd statement -> you can find the radius because you get the radius from it
