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apollo168
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ps_dahiya
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apollo168
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apollo168
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But as always I would love to hear your explanation. I arrived at B by simply plugging in the values to the equation. I have a feeling that that isnt the correct way to go about it
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kevincan
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The two statements contradict each other. If r=3 and s=2, how can 3r+2s=6?
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jjhko
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Is the answer E b/c the question is assuming that there are two different planes to consider here? i.e. plane-xy vs. plane-rs?

Seems like a trick question.
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defenestrate
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It does seem like a trick question, but what other information do we need beside the value of r and s? We are to assume that all lines exist on the same plane unless otherwise stated...
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I get B:

For a line to belong in region RS, the points x,y must lie on the line 2x+3y=6
This means that the y-value must satisfy
y=-2x/3+2...(1)

1: 3r + 2s = 6. r, s = {r, -3r/2+3}

For (1) to hold,
-3r/2+3 = -2r/3+2
Or
r=2....we don't know this hence INSUFF

From (2)

We can plug in r for x and s for y and see that either this holds or it does not, so this is ennough to answer hence SUFF



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