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31 Jul 2019, 02:06
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B
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Difficulty:
25%
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Question Stats:
82% (02:18) correct
18%
(03:31)
wrong
based on 73
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In the year 2001, a company's sales increased by x percent from the year 2000. In 2002, sales decreases x percent from the year 2001. If the sales in 2002 is 9 percent less than that in 2000, what is x?
A. 20
B. 30
C. 40
D. 50
E. 60
A. 20
B. 30
C. 40
D. 50
E. 60
31 Jul 2019, 02:34
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Bunuel
In the year 2001, a company's sales increased by x percent from the year 2000. In 2002, sales decreases x percent from the year 2001. If the sales in 2002 is 9 percent less than that in 2000, what is x?
A. 20
B. 30
C. 40
D. 50
E. 60
A. 20
B. 30
C. 40
D. 50
E. 60
Given: In the year 2001, a company's sales increased by x percent from the year 2000. In 2002, sales decreases x percent from the year 2001. If the sales in 2002 is 9 percent less than that in 2000,
Asked: what is x?
If sales in 2000 = 1
Sales in 2002 = (1+x)(1-x) = 1+x-x-x^2 = 1-x^2
x^2 = .09
x=.3 = 30%
IMO B
31 Jul 2019, 02:47
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Let’s say that
—sales in 2000 is 100$;
—(increased by x percent) sales in 2001 is (100+x);
—(decreased by x percent) sales in 2002 is (100+x)—(100+x)*(x/100)=(100+x)*(1–x/100)=(100^2-x^2)/100
It says that sales in 2002 is 9 percent less than that in 2000
—> 100–9=91
(100^2–x^2)/100=91
x^2=100^2–91*100=900
x=30
The answer choice is B
Posted from my mobile device
—sales in 2000 is 100$;
—(increased by x percent) sales in 2001 is (100+x);
—(decreased by x percent) sales in 2002 is (100+x)—(100+x)*(x/100)=(100+x)*(1–x/100)=(100^2-x^2)/100
It says that sales in 2002 is 9 percent less than that in 2000
—> 100–9=91
(100^2–x^2)/100=91
x^2=100^2–91*100=900
x=30
The answer choice is B
Posted from my mobile device
