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bmwhype2
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bmwhype2
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bmwhype2
given that y>0 and y(y+1) > y(y-4), solve for the possible values of y.

y(y+1) > y(y-4) if i were to cancel out y from both sides, it would result in a different answer. what rule am i volating?

y(y+1) - y(y-4)> 0

ans: y>0

Distribute the y's: y^2+y>y^2-4y --> y>-4y --> 0>-5y --> 0<y

Or y>0
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Good question.

I think it means that the inequality is true for all values of Y. This plus the given, Y>0, leaves us with the same answer as solving by the less risky method. Y>0.
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bmw, I get what you're asking.

the answer is that no, you cannot just divide both sides by a variable in an inequality because of sign changes. EVEN THOUGH we're given that y > 0, mathetically you shouldn't apply that to the equation.
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zhenmaster
bmw, I get what you're asking.

the answer is that no, you cannot just divide both sides by a variable in an inequality because of sign changes. EVEN THOUGH we're given that y > 0, mathetically you shouldn't apply that to the equation.
https://www.urch.com/forums/gmat-math/8 ... ities.html



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