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Senior Manager
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Inequalities [#permalink]

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New post 08 Oct 2008, 01:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Please explain the different approaches for solving :

|5x - 2| <= 3x + 1
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rampuria

Kudos [?]: 98 [0], given: 9

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Re: Inequalities [#permalink]

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New post 08 Oct 2008, 02:19
rampuria wrote:
Please explain the different approaches for solving :

|5x - 2| <= 3x + 1


this question is asking for rage of values of X which satisfy this equation. Mode indicate two values for (5x-2)
1) +ive
5x-2<=3x+1
2x<=3
x<=3/2
2) -ive
-5x+2<=3x+1
8x=>1
X=>1/8

by both range of would be 1/8<=X<=3/2

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Senior Manager
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Posts: 251

Kudos [?]: 98 [0], given: 9

Location: Kolkata
Schools: La Martiniere for Boys
Re: Inequalities [#permalink]

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New post 08 Oct 2008, 09:15
In the first case you are assuming 5x - 2 as positive i.e. >= 0. That means x >= 2/5

In the second case you are assuming 5x - 2 < 0 so x < 2/5

How would you summarise the above along with your solutions
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rampuria

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Re: Inequalities [#permalink]

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New post 09 Oct 2008, 06:04
rampuria wrote:
Please explain the different approaches for solving :

|5x - 2| <= 3x + 1


two cases for |5x-2|. It can be +(5x-2) or -(5x-2)

case 1

5x-2 <= 3x+1
2x <= 3
x <= 3/2

case 2

-(5x-2) <= 3x+1
-5x+2 <= 3x+1
1 <= 8x
x>= 1/8

so x lies between 1/8 and 3/2
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Re: Inequalities   [#permalink] 09 Oct 2008, 06:04
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