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# Inequalities

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Manager
Joined: 04 Sep 2008
Posts: 238
Location: Kolkata
Schools: La Martiniere for Boys

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08 Oct 2008, 01:54
Please explain the different approaches for solving :

|5x - 2| <= 3x + 1

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rampuria

Senior Manager
Joined: 05 Jun 2008
Posts: 292

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08 Oct 2008, 02:19
rampuria wrote:
Please explain the different approaches for solving :

|5x - 2| <= 3x + 1

this question is asking for rage of values of X which satisfy this equation. Mode indicate two values for (5x-2)
1) +ive
5x-2<=3x+1
2x<=3
x<=3/2
2) -ive
-5x+2<=3x+1
8x=>1
X=>1/8

by both range of would be 1/8<=X<=3/2
Manager
Joined: 04 Sep 2008
Posts: 238
Location: Kolkata
Schools: La Martiniere for Boys

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08 Oct 2008, 09:15
In the first case you are assuming 5x - 2 as positive i.e. >= 0. That means x >= 2/5

In the second case you are assuming 5x - 2 < 0 so x < 2/5

How would you summarise the above along with your solutions
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rampuria

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Joined: 30 Jun 2008
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09 Oct 2008, 06:04
[quote="rampuria"]Please explain the different approaches for solving :

|5x - 2| = 1/8

so x lies between 1/8 and 3/2

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Re: Inequalities   [#permalink] 09 Oct 2008, 06:04
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# Inequalities

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