Last visit was: 25 Apr 2026, 09:47 It is currently 25 Apr 2026, 09:47
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
mdf2
Joined: 11 Jan 2005
Last visit: 28 Jul 2005
Posts: 48
Own Kudos:
Posts: 48
Kudos: 3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
christoph
Joined: 30 Sep 2004
Last visit: 23 Nov 2011
Posts: 684
Own Kudos:
Location: Germany
Posts: 684
Kudos: 1,587
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Vijo
Joined: 01 Jan 2005
Last visit: 11 Jul 2005
Posts: 76
Own Kudos:
Location: NJ
Posts: 76
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
rxs0005
Joined: 07 Jun 2004
Last visit: 21 Jun 2017
Posts: 436
Own Kudos:
Given Kudos: 22
Location: PA
Posts: 436
Kudos: 3,310
Kudos
Add Kudos
Bookmarks
Bookmark this Post
the only even prime num = 2

rest all odd startign from 3

1 not a prime
avatar
HongHu
Joined: 03 Jan 2005
Last visit: 25 Apr 2011
Posts: 962
Own Kudos:
Posts: 962
Kudos: 798
Kudos
Add Kudos
Bookmarks
Bookmark this Post
1 is not a prime number. But if asked how many divisors a number has, 1 would be counted. Am I correct?
User avatar
banerjeea_98
Joined: 18 Nov 2004
Last visit: 17 May 2012
Posts: 674
Own Kudos:
Posts: 674
Kudos: 201
Kudos
Add Kudos
Bookmarks
Bookmark this Post
HongHu
1 is not a prime number. But if asked how many divisors a number has, 1 would be counted. Am I correct?


Ya, 1 is a factor of all, but not prime.
User avatar
nocilis
Joined: 19 Nov 2004
Last visit: 11 Jul 2008
Posts: 274
Own Kudos:
Location: SF Bay Area, USA
Posts: 274
Kudos: 1,545
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Also, all prime numbers other than 2 and 3 can be represented as 6n-1 or 6n+1 (n>=1).

But bewarned, not all numbers that can be represented as 6n-1 or 6n+1 are primes, such as number 91 (13X7) which is not prime.
User avatar
MA
Joined: 25 Nov 2004
Last visit: 09 Aug 2011
Posts: 695
Own Kudos:
Posts: 695
Kudos: 533
Kudos
Add Kudos
Bookmarks
Bookmark this Post
prime is divided by itself and 1. prime must have 2 dividers, one, itself and another, 1. on the ground that it (1) has not two dividers, it is not considered as prime.
avatar
HongHu
Joined: 03 Jan 2005
Last visit: 25 Apr 2011
Posts: 962
Own Kudos:
Posts: 962
Kudos: 798
Kudos
Add Kudos
Bookmarks
Bookmark this Post
nocilis
Also, all prime numbers other than 2 and 3 can be represented as 6n-1 or 6n+1 (n>=1).

But bewarned, not all numbers that can be represented as 6n-1 or 6n+1 are primes, such as number 91 (13X7) which is not prime.


Wow. How do you know that? Is there a prove somewhere?

Let me see ... Ok, all numbers can be written as 6n, 6n+1, 6n+2, 6n+3, 6n+4, 6n+5. And obviously 6n, 6n+2, 6n+3, 6n+4 are not prime numbers. So the only thing that is left would be 6n+1 and 6n+5 (or 6n-1).

That's pretty cool.

By the same token, all prime numbers can be written as 4n-1 and 4n+1 too. Though it may not be that much helpful.
User avatar
anirban16
Joined: 24 Jan 2005
Last visit: 20 Jun 2005
Posts: 141
Own Kudos:
Location: Boston
Posts: 141
Kudos: 72
Kudos
Add Kudos
Bookmarks
Bookmark this Post
2 is the smallest prime number.

Good logic for 6n and 4n stuff.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!