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Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in

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Bunuel
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Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in [#permalink] New post   13 Apr 2018, 02:05
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Is 2k > 13?

(1) 6 < k - 0.6 < 7
(2) k + 0.8 rounded to the nearest integer is 8.
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D
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NiharikaR
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Re: Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in [#permalink] New post   13 Apr 2018, 02:10
IMO D

St1
6.6<k<7.6
13.2<2k<15.2
sufficient

St2
rounded to nearest 8 means no is from 7.5(included) to 8.5(excluded)
7.5<=k+0.8<8.5
6.7<=k<7.7
2k>13.4
Sufficient
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Re: Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in [#permalink] New post   13 Apr 2018, 02:12
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Bunuel wrote:
Is 2k > 13?

(1) 6 < k - 0.6 < 7
(2) k + 0.8 rounded to the nearest integer is 8.


Question asks is 2K > 13 or Is K > 6.5 ?

(1) 6 < k - 0.6 < 7 ... add 0.6 to all sides of ineq

6 + 0.6 < k < 7 + 0.6
6.6 < k < 7.6

Hence k > 6.5 Sufficient

(2) let k be 6.6

6.6 + 0.8 = 7.4 ( rounded to nearest integer is 7) so k must be greater than 6.6 hence greater than 6.5 also! Hence Suff

Hence Option (D) is our answer.

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Re: Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in [#permalink] New post   28 Apr 2018, 06:20
As per question we want to find K>6.5

I) solving yield 6.6<k<7.6
Sufficient

II)value needs to be min 6.7 so as to +0.8 would yield 7.5 which will round up to 8 as integer

Sufficient

D is answer

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Re: Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in [#permalink] New post   12 Jul 2018, 05:04
Bunuel wrote:
Is 2k > 13?

(1) 6 < k - 0.6 < 7
(2) k + 0.8 rounded to the nearest integer is 8.


Can anybody confirm For statement 2 "

Range of K+0.8 should be what ?

7.5 \(\leq\) k + 0.8 \(\leq\) 8.4
7.5 \(\leq\) k + 0.8 \(\leq\) 8.5
I think it should be the first one , as for 8.5 nearest integer is 9 and not 8 . Thank you.
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Re: Is 2k > 13? (1) 6 < k - 0.6 < 7 (2) k + 0.8 rounded to the nearest in [#permalink]
12 Jul 2018, 05:04
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Bunuel
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