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C
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Difficulty:
15%
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Question Stats:
82% (01:23) correct
18%
(01:37)
wrong
based on 128
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Is 3x − y + z greater than 2x − y + 2z?
(1) x is positive.
(2) (x^2)*z is negative.
(1) x is positive.
(2) (x^2)*z is negative.
25 Feb 2012, 23:58
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Is 3x − y + z greater than 2x − y + 2z?
(1) x is positive. No info about \(z\). Not sufficient.
(2) (x^2)*z is negative --> \((x^2)*z<0\) --> \(z\) is negative, but limited info about \(x\) (we only know that \(x\neq{0}\)). Not sufficient.
(1)+(2) From (1) \(x\) is positive and from (2) \(z\) is negative --> \(x>z\). Sufficient.
Answer: C.
- Is \(3x-y+z>2x-y+2z\)?
Is \(x>z\)?
(1) x is positive. No info about \(z\). Not sufficient.
(2) (x^2)*z is negative --> \((x^2)*z<0\) --> \(z\) is negative, but limited info about \(x\) (we only know that \(x\neq{0}\)). Not sufficient.
(1)+(2) From (1) \(x\) is positive and from (2) \(z\) is negative --> \(x>z\). Sufficient.
Answer: C.
26 Feb 2012, 13:59
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Bunuel
How did you deduce z must be negative?
From exponent rule, \(b^(-n)\) is \(1/b^n\). This will always be positive if n is even, regardless of the base. Since \(n = 2z\), \(x^(2*z)\) will always be positive, which contradicts the original statement #2. Am I missing something here?
