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Is 7 < n^(1/2) < 8?

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Is 7 < n^(1/2) < 8? [#permalink]

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New post 17 Aug 2010, 08:45
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Is \(7 < \sqrt n < 8\)?

(1) n > 50

(2) n < 60
[Reveal] Spoiler: OA

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Re: Is 7 < n^(1/2) < 8? [#permalink]

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New post 17 Aug 2010, 08:54
cmugeria wrote:
IS 7 < SQRT N < 8?

1) N>50
2) N<60


Is \(7<\sqrt{n}<8\) --> or is \(49<n<64\).

(1) \(n>50\). Not sufficient as \(n\) can be more than 64.

(2) \(n<60\). Not sufficient as \(n\) can be less than 49.

(1)+(2) \(50<n<60\). Sufficient.

Answer: C.
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Re: Is 7 < n^(1/2) < 8? [#permalink]

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New post 17 Aug 2010, 22:28
Consider 1)+2) we have (50;60) interval.

_______49__50_______60____64

But what to do with highlighted parts?
Virtually we are asked if 49<N<64?
we miss 2 intervals: (49;50) and (60;64)
Having (50;60) we can't say that (49;64) is true.
Looks like (E).

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Re: Is 7 < n^(1/2) < 8? [#permalink]

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New post 18 Aug 2010, 04:19
ulm wrote:
Consider 1)+2) we have (50;60) interval.

_______49__50_______60____64

But what to do with highlighted parts?
Virtually we are asked if 49<N<64?
we miss 2 intervals: (49;50) and (60;64)
Having (50;60) we can't say that (49;64) is true.
Looks like (E).


OA for this question is C.

Question: is \(49<n<64\)? or is \(n\) in the range (49,64), not inclusive.

(1)+(2) \(50<n<60\) --> ANY \(n\) (any number) from this range IS in the range (49,64), so the answer to the question "is \(49<n<64\)" is YES.

Hope it's clear.
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Re: Is 7 < n^(1/2) < 8? [#permalink]

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Re: Is 7 < n^(1/2) < 8?   [#permalink] 14 Aug 2017, 05:32
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