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# Is a > (3b)/2, where a and b are real numbers? (1) b < a/2 (2) a and

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DS Forum Moderator
Joined: 21 Aug 2013
Posts: 1412
Location: India
Is a > (3b)/2, where a and b are real numbers? (1) b < a/2 (2) a and  [#permalink]

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23 Jul 2018, 20:11
1
00:00

Difficulty:

75% (hard)

Question Stats:

42% (01:42) correct 58% (01:28) wrong based on 53 sessions

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Is a > (3b)/2, where a and b are real numbers?

(1) b < a/2

(2) a and b are non zero integers.
MBA Section Director
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 1425
Concentration: Nonprofit
GPA: 4
WE: Engineering (Computer Software)
Re: Is a > (3b)/2, where a and b are real numbers? (1) b < a/2 (2) a and  [#permalink]

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23 Jul 2018, 21:22
To find whether a > $$\frac{3b}{2}$$

Statement 1

b < $$\frac{a}{2}$$

=> $$\frac{a}{2}$$ > b

=> a > 2b

=> a > $$\frac{4b}{2}$$

=> a > $$\frac{3b}{2}$$

Statement 1 is sufficient

Statement 2

a and b are non zero integers

=> a can be 1 and b can be -1 => a > $$\frac{3b}{2}$$

=> a can be -1 and b can be 1 => a < $$\frac{3b}{2}$$

Statement 2 is not sufficient

Hence option A
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Manager
Joined: 22 Jan 2014
Posts: 175
WE: Project Management (Computer Hardware)
Re: Is a > (3b)/2, where a and b are real numbers? (1) b < a/2 (2) a and  [#permalink]

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30 Jul 2018, 08:21
amanvermagmat wrote:
Is a > (3b)/2, where a and b are real numbers?

(1) b < a/2

(2) a and b are non zero integers.

Is a > 3b/2
or is 2a > 3b ?

1) b < a/2
or 2b < a
(a,b) = (3,1) --> 2a > 3b (yes)
(a,b) = (-1/2 , -1/3) --> 2a = 3b (no)
insuff.

2) a,b are integers (<>0)
insuf

1) + 2)
(a,b) = (3,1) --> 2a > 3b (yes)
(a,b) = (-3,-2) --> 2a = 3b (no)
insuff.
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Illegitimi non carborundum.

Re: Is a > (3b)/2, where a and b are real numbers? (1) b < a/2 (2) a and &nbs [#permalink] 30 Jul 2018, 08:21
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