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13 Sep 2020, 10:01
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
23% (00:51) correct
77%
(01:16)
wrong
based on 13
sessions
History
Date
Time
Result
Not Attempted Yet
Is a<b?
1) |a - b|= b - a
2) \(\frac{a}{b}\) < 1
Solution:
Source:
GMAT Club webinar (e-gmat) https://youtu.be/jCDBIB9lkAQ?t=4288
Hoping someone can clear this up for me. The e-gmat webinar determined the answer to be C, but I don't see how it isn't E.
Scenario 1: a and b could both be 0, thus a is not less than b
1) |0-0| = 0 - 0
2) 0/0 < 1
Scenario 2: a could also be less than b (say, a=-3 and b=5)
1) |(-3 ) - (5)| = 5 - (-3), simplified to |-8| = 8
2) -3/5 < 1
These two different scenarios can't prove that a is or isn't less than b. Where'd I go wrong?
1) |a - b|= b - a
2) \(\frac{a}{b}\) < 1
Solution:
Attachment:
Screen Shot 2020-09-13 at 11.52.50 AM.png
GMAT Club webinar (e-gmat) https://youtu.be/jCDBIB9lkAQ?t=4288
Hoping someone can clear this up for me. The e-gmat webinar determined the answer to be C, but I don't see how it isn't E.
Scenario 1: a and b could both be 0, thus a is not less than b
1) |0-0| = 0 - 0
2) 0/0 < 1
Scenario 2: a could also be less than b (say, a=-3 and b=5)
1) |(-3 ) - (5)| = 5 - (-3), simplified to |-8| = 8
2) -3/5 < 1
These two different scenarios can't prove that a is or isn't less than b. Where'd I go wrong?
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13 Sep 2020, 10:25
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Hey Coinsy,
Statement (1) taken alone
we can have
|a-b| = b - a
Condition 1: take a=b=3 or 4 or any other number
Then |3-3| = 3-3 = 0
Condition 2: Take a=1 and b =4
then |1-4| = 4-1 = 3
Condition 3: Take a=4 and b=1
the |4-1| = 3
1-4= -3
Condition three is not valid
Also |a-b| is always positive
so if b-a is always positive it means that b>a (excluding the case where the are equal)
So (1) is not sufficient as condition says that a=b and condition (2) says that a<b. Hence statement 1 is not sufficient
Statement (2)
a/b < 1
Condition 1: a=-5 and b = -10
this proves a/b < 1 as 0.5 < 1
but clearly a>b
Condition 2: a=5 and b =10
this proves a/b < 1 as 0.5 < 1
so a<b
Hence Statement (2) alone is not sufficient
Now consider (1) and (2) together
Recall that statement 1 is insufficient because we got 2 different values of a=b and a<b
similarly statement 2 is insufficient because we didn't know the sign of the a and b
Now a cannot be equal b because the statement 2 will be invalid similarly a>b then statement 1 will be valid
So combining both the statements we can say that a<b
hence the answer is C
Kudos if it helps
Statement (1) taken alone
we can have
|a-b| = b - a
Condition 1: take a=b=3 or 4 or any other number
Then |3-3| = 3-3 = 0
Condition 2: Take a=1 and b =4
then |1-4| = 4-1 = 3
Condition 3: Take a=4 and b=1
the |4-1| = 3
1-4= -3
Condition three is not valid
Also |a-b| is always positive
so if b-a is always positive it means that b>a (excluding the case where the are equal)
So (1) is not sufficient as condition says that a=b and condition (2) says that a<b. Hence statement 1 is not sufficient
Statement (2)
a/b < 1
Condition 1: a=-5 and b = -10
this proves a/b < 1 as 0.5 < 1
but clearly a>b
Condition 2: a=5 and b =10
this proves a/b < 1 as 0.5 < 1
so a<b
Hence Statement (2) alone is not sufficient
Now consider (1) and (2) together
Recall that statement 1 is insufficient because we got 2 different values of a=b and a<b
similarly statement 2 is insufficient because we didn't know the sign of the a and b
Now a cannot be equal b because the statement 2 will be invalid similarly a>b then statement 1 will be valid
So combining both the statements we can say that a<b
hence the answer is C
Kudos if it helps
13 Sep 2020, 10:32
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logro
Thanks for the reply
These conditions show a<b, but why can’t a and b both be zero? In which case a is not less than b?
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