Bunuel
Is ab + cd > 0 ?
(1) ac + bd >0
(2) bc + ad >0
Questions such as this can be quite consuming if one gets entangled in the world of picking numbers. While picking numbers works just fine, we can use logic to work our way through.
Having said that, it is very evident from the questions and the statements presented, that statement 1 and statement 2 are not individually sufficient. Hence the answer can either be C or E. A 50 - 50 chance is not bad for a question that may otherwise take time !
Statement 1 Given ac + bd >0.
If all the numbers are positive the response to the question ab + cd > 0 will be yes. This interpretation is quite straightforward, hence we need not spend any time testing a scenario in which a, b, c and d are positive.
However there can be a scenario, in which the numbers lie on opposite side of zero. Example -
-------- b ---- d ----------------------- c -- 0 ---- a ------
In this case, while ac + bd >0, ab + cd < 0
The statement is not sufficient and we can eliminate A and D.
Statement 2 bc + ad >0
Quite similar analysis to Statement 1.
If all values are positive, we get ab + cd > 0 .
However, we can have a possibility in which ab + cd < 0
-------- a ---- d ----------------------- c -- 0 ---- b ------
Not sufficient.
Combinedac + bd >0
bc + ad >0
(a+b)(c+d) > 0
Just as in Statement 1, if all the numbers are positive, the response to the question Is ab + cd > 0 is Yes !
However, if (a+b) and (c+d) result in negative values, we can have ab + cd < 0.
Hence the statements combined is not sufficient.
Option E