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13 Nov 2014, 09:40
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:19) correct
29%
(01:24)
wrong
based on 145
sessions
History
Date
Time
Result
Not Attempted Yet
Tough and Tricky questions: Algebra.
Is \(abc = 2\)?
(1) \(ab = 2\)
(2) \(bc = 2\)
Kudos for a correct solution.
13 Nov 2014, 09:53
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statement 1: not sufficient
AB=2 does not let us know anything about C
statement 2: not sufficient
BC=2 does not let us know anything about a
Down to answer choices C and E.
Combined, we still do not have enough information. If a=-1, b=-2, and c=-1, then abc=-2. If a=1, b=2, and c=1, then abc=2.
Answer choice E!
AB=2 does not let us know anything about C
statement 2: not sufficient
BC=2 does not let us know anything about a
Down to answer choices C and E.
Combined, we still do not have enough information. If a=-1, b=-2, and c=-1, then abc=-2. If a=1, b=2, and c=1, then abc=2.
Answer choice E!
13 Nov 2014, 13:38
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These type of statements I try to see if I can solve using +/- rather than plugging numbers, but both work in this case.
+/- approach
Statement 1:
ab = 2
either both a >0 and b>0 = 2 or both a<0 and b<0 = 2. i.e. 1*2 or -1*-2
Insufficient
Statement 2:
cb=2
same as statement 1
Insufficient
Combining the the two:
a,b and c may all be negative so they would equal -2 not 2
or a,b and c may all be positive and equal 2.
Insufficient.
So E
# plugging
Statement 1:
set a = 1/2 b= 4 so ab = 2. Or a= 1 and b=2 so ab = 2.
Statement 2:
same as statement 1
if a and c both = 1/2 then abc=1 or if a and c both = 1 then abc = 2
So E again.
+/- approach
Statement 1:
ab = 2
either both a >0 and b>0 = 2 or both a<0 and b<0 = 2. i.e. 1*2 or -1*-2
Insufficient
Statement 2:
cb=2
same as statement 1
Insufficient
Combining the the two:
a,b and c may all be negative so they would equal -2 not 2
or a,b and c may all be positive and equal 2.
Insufficient.
So E
# plugging
Statement 1:
set a = 1/2 b= 4 so ab = 2. Or a= 1 and b=2 so ab = 2.
Statement 2:
same as statement 1
if a and c both = 1/2 then abc=1 or if a and c both = 1 then abc = 2
So E again.
