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Re: Is c = d ? (1) cd = 1 (2) |c| = d [#permalink]
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    Ans. C
    1) Stmt 1:
    cd=1
    d=1/c
    so, possibilities include: c=2, d=1/2 OR c=1, d=1
    Therefore, c=d OR c!=d
    Not sufficient

    2) Stmt 2:
    |c| = d
    c=d OR c=-d
    Therefore, c=d OR c!=d
    Not sufficient

    Combining 1 + 2:

    c=d, cd=1 means c^2=1 OK
    c=-d cd=1 means c^2=-1 Not a solution(complex)
    Hence, c=d
    C gives us the answer

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Re: Is c = d ? (1) cd = 1 (2) |c| = d [#permalink]
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Kudos
I need a confirmation here please.

When encountering a DS problem like our example here, I managed to get “Yes/No” answer to each statement. I mean that I managed to prove that each statement is insufficient. So, so far the answer choice shiuld be E.

However, if there is only one answer that can fit both statements ,as in our case here if c=d=1 that proves, then we can conclude that the correct choice is C?

In other words, whenever if one can proves that both statements are insufficient, but if we have just one choice that can fit both statements, then the correct answer choice will always be C not E, am I correct here?

Thanks

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Re: Is c = d ? (1) cd = 1 (2) |c| = d [#permalink]
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Re: Is c = d ? (1) cd = 1 (2) |c| = d [#permalink]
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