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Is J + K > L + M ?

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Joined: 27 Mar 2013
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Is J + K > L + M ?  [#permalink]

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New post 23 Sep 2014, 12:18
7
00:00
A
B
C
D
E

Difficulty:

  75% (hard)

Question Stats:

43% (01:27) correct 57% (00:53) wrong based on 139 sessions

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Is J + K > L + M ?

(1) J > L + M

(2) K > L + M
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Re: Is J + K > L + M ?  [#permalink]

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New post 23 Sep 2014, 12:44
gmatquant25 wrote:
Is J+k> L+M

1) J> L+M

2) K>L+M


This question is testing your understanding of number properties. At first glance it seems obvious that the answer would be D (both statements alone). But upon further thought, you would find that there is no restriction that the numbers have to be positive. Therefore, it is possible that any of the numbers could be negative. Knowing that, if we try to plug in some extreme examples we find that we cannot prove the statement and the correct answer is E. Here are some sample numbers I tried to plug in.

Statement 1:

J = 3
L = 2
M = 1
K = 100 or -100
Using one value of K gives me TRUE, using the second value gives me FALSE. Therefore Statement 1 is insufficient.

Statement 2:
Just like Statement 1, but switch J and K.

K = 3
L = 2
M = 1
J = 100 or -100
Using one value of J gives me TRUE, using the second value gives me FALSE. Therefore Statement 2 is insufficient.
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Re: Is J + K > L + M ?  [#permalink]

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New post 24 Sep 2014, 04:55
But what makes E correct, and why not C?
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Re: Is J + K > L + M ?  [#permalink]

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New post 24 Sep 2014, 05:42
3
1
nelo5390 wrote:
But what makes E correct, and why not C?


Is J + K > L + M ?

(1) J > L + M. If J = K = 1 and L + M = 0, then J + K > L + M but if If J = 1, K = -1 and L + M = 0, then J + K = L + M. Not sufficient.

(2) K > L + M. If J = K = 1 and L + M = 0, then J + K > L + M but if If J = -1, K = 1 and L + M = 0, then J + K = L + M. Not sufficient.

(1)+(2):

If J = K = 1 and L + M = 0, then J + K > L + M
If J = K = -1 and L + M = -2, then J + K = L + M.

Not sufficient.

Answer: E.
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Re: Is J + K > L + M ?  [#permalink]

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New post 26 Sep 2014, 10:51
1
1
gmatquant25 wrote:
Is J + K > L + M ?

(1) J > L + M

(2) K > L + M


we can clearly see 1 and 2 alone are insufficient.

(1)+(2)

assume all terms are +ve
add the inequality
(j+k) > 2(l+m)

assume all terms are -ve
add the inequality
(j+k) < 2(l+m)

so E. :)
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Re: Is J + K > L + M ?  [#permalink]

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New post 14 Jul 2017, 10:18
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Re: Is J + K > L + M ?   [#permalink] 14 Jul 2017, 10:18
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