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Re: Is k a multiple of 14? (1) k > 13! (2) k = m!, where m is an integer g [#permalink]
St1: k > 13!

We are not told that k is an integer. Numerous possibilities galore.
Not sufficient.

St2: k = m!, where m is an integer greater than 6

Let's take m = 7
7! has 2 and 7 so k will be a multiple of 14.

For all integers m > 7, k will at least have a 2 and a 7 so it will always be a multiple of 14.
Sufficient.

Answer (B).
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Re: Is k a multiple of 14? (1) k > 13! (2) k = m!, where m is an integer g [#permalink]
1
Kudos
Statement 1 => let K be K!+0.243974979270 => clearly this isn't a multiple of 14
Statement 2 => K must be an integer and k must be at-least 7! because of the ! sign => a 2 and a 7 must be present in K all times.
Suff.
Smash that B
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Re: Is k a multiple of 14? (1) k > 13! (2) k = m!, where m is an integer g [#permalink]
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Re: Is k a multiple of 14? (1) k > 13! (2) k = m!, where m is an integer g [#permalink]
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