Bunuel wrote:

Is k an odd integer?

(1) k is an integer divisible by 3.

(2) The square root of k is an integer divisible by 3.

E is the answer as follows

(1) k is an integer divisible by 3

Let k=3m => k=

0,

3,

6,

9,

12,

15,

18,

21,

24,

27,

30, ...........................

The numbers marked in

RED are odd and the numbers marked in

BLUE are even

NOT SUFFICIENT

(2) The square root of k is an integer divisible by 3

Let k=9\(n^2\) =

0,

9,

36,

81,

144,..........

\(\sqrt{k}\) = 0,3,6,9,12

NOT SUFFICIENT

Combining both the conditions we get k =

0,

9,

36,

81,

144,..........

Clearly, some numbers are odd and some are even.

Hence, NOT SUFFICIENT

E is the answer

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