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Bunuel
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Bunuel
Is m > n?


(1) 3/7 < m < 5/7

(2) 2/7 < n < 4/7

from 1: we can say 21<m<35
From 2: 14<n<28

so combing 1 & 2 m can be equal to n at an y value 22 to 27 , so in sufficient.. IMO E


Hello

from (1), can you please check how you have concluded 21 < m < 35?
To get 21 on the left, we will need to multiply the entire inequality by 49. That will give us: 21 < 49m < 35.

Similarly in (2), we need to multiply entire inequality by 49 to get 14 and 28. We will get: 14 < 49n < 28.

So then we can compare 49m and 49n with each other. Result will still be E, as you have concluded - but I thought I should point this out.
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Bunuel
Is m > n?


(1) 3/7 < m < 5/7

(2) 2/7 < n < 4/7

from 1: we can say 21<m<35
From 2: 14<n<28

so combing 1 & 2 m can be equal to n at an y value 22 to 27 , so in sufficient.. IMO E


Hello

from (1), can you please check how you have concluded 21 < m < 35?
To get 21 on the left, we will need to multiply the entire inequality by 49. That will give us: 21 < 49m < 35.

Similarly in (2), we need to multiply entire inequality by 49 to get 14 and 28. We will get: 14 < 49n < 28.

So then we can compare 49m and 49n with each other. Result will still be E, as you have concluded - but I thought I should point this out.

Yes I missed including 49m and 49n.. answer would still be E..

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