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Bunuel
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satya2029
Bunuel
Is \(\frac{m}{n^2+1} > \frac{n}{m^2+2}\)?

(1) \(m = n\)
(2) \(n < 0\)

Are You Up For the Challenge: 700 Level Questions
From 1
m=n=0
0>0 NO
m=n=1
1/2>1/3 YES
From 2
m=n=-1
-1/2>-1/3 NO
m=5 n =-1/2
5/2>-1/27 YES
m=n=-1/2
1/5>1/9 YES
FROM 1 AND 2
m=n=-1 NO
m=n=-1/2 YES
E:)


Not satisfactory for B if we use N<0 then one part simply becomes negative....no point in assuming m

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avirup2018
Why are u assuming m when nothing is said about m only thing is said is about n<0....

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Just to observe each and every case. In this way you actually test statement 1 within statement 2.
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I think together it makes sense, say n=-1=m, then always, first half < second half. Sufficient to answer the questions.
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first consider statement 1 alone:
given m=n
if we substitute we get
m/(m^2+1)>m/(m^2+2)
we can observe that denominator of LHS is lesser than denominator of RHS
but we dont know whether m>0 or m<0
so there is no unique answer.

Now consider statement 2 alone:
given n<0
here we do not have definite relationship between m,n
and also we no nothing about m
hence no unique answer.

Now consider both statements together:
m=n and n<0 implies m<0
substituting we get
m/(m^2+1)>m/(m^2+2)
since we know that m<0
we get unique answer

hence answer is C
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