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Is m+z > 0? 1) m - 3z > 0 2) 4z - m > 0

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Intern
Joined: 23 Jun 2009
Posts: 47
Is m+z > 0? 1) m - 3z > 0 2) 4z - m > 0 [#permalink]

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26 Jul 2009, 21:43
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Is m+z > 0?

1) m - 3z > 0
2) 4z - m > 0
Manager
Joined: 19 Jun 2009
Posts: 141
Location: India
Concentration: Strategy, General Management
GMAT 1: 650 Q51 V27
GMAT 2: 710 Q48 V39
GPA: 3.2
WE: Engineering (Computer Hardware)
Re: DS PROBLEM #9. ANYONE? [#permalink]

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26 Jul 2009, 22:52
uzonwagba wrote:
Is m+z > 0?

1) m - 3z > 0
2) 4z - m > 0

1. It only tells us - m > 3z. But, if both are negative m+3z can be negative. So, not sufficient.

2. Same reason as above. Not sufficient.

1+2. Add both sentences. We get,

z>0. Now, we know z is positive. Using, 1 we can deduct m is positive. Hence, m+z is positive for sure.

Answer = C. Both sentences are necessary.

Am I correct ? What is OA ?
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Intern
Joined: 23 Jun 2009
Posts: 47
Re: DS PROBLEM #9. ANYONE? [#permalink]

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26 Jul 2009, 22:58
alpeshvc wrote:
uzonwagba wrote:
Is m+z > 0?

1) m - 3z > 0
2) 4z - m > 0

1. It only tells us - m > 3z. But, if both are negative m+3z can be negative. So, not sufficient.

2. Same reason as above. Not sufficient.

1+2. Add both sentences. We get,

z>0. Now, we know z is positive. Using, 1 we can deduct m is positive. Hence, m+z is positive for sure.

Answer = C. Both sentences are necessary.

=Am I correct ? What is OA ?

You are correct! Thanks! However, I would appreciate your shedding more light on your statement "1. It only tells us - m > 3z. But, if both are negative m+3z can be negative. So, not sufficient." Please explain with a little more detail how this is so.
Re: DS PROBLEM #9. ANYONE?   [#permalink] 26 Jul 2009, 22:58
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