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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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GMAT Focus 1: 735 Q90 V89 DI81
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IMO D
From I, we can determine that the shape is a square, and all squares are rhombuses.
From II, we can determine that the shape is a rhombus since a circle cannot be inscribed in quadrilaterals with unequal adjacent sides. Since ABCD is a parallelogram (so cannot be a kite) and therefore a rhombus.
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