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one more thought!

1). if pq>0 then p & q are both negative or both positive (still insufficient)
2). q/r<0. Lest multiply both sides by r^2 (no sign change) then we have qr<0 (still insufficient)

but combined we have 2 sets of variables and their signs:
1. p+ q+ r- then pqr<0
2. p- q- r+ then pgr>0

only now having 2 possibilities can state that E is correct!
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Is pqr > 0 ?

(1) pq > 0 --> p and q have the same sign, but we now nothing about r, so this statement is insufficient.

(2) q/r < 0 --> q and r have the opposite signs, but we now nothing about p, so this statement is insufficient.

(1)+(2)If p and q are both positive and r is negative then pqr=positive*positive*negative=negative BUT if p and q are both negative and r is positive then pqr=negative*negative*positive=positive. Not sufficient.

Answer: E.

Hope it's clear.
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1+2,

p q r pqr
- - + +
+ + - -

hence E, pqr can be + or - that is pqr can be >0 or <0.
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Bunuel
Is pqr > 0 ?

(1) pq > 0 --> p and q have the same sign, but we now nothing about r, so this statement is insufficient.
(2) q/r < 0 --> q and r have the opposite signs, but we now nothing about p, so this statement is insufficient.

(1)+(2)If p and q are both positive and r is negative then pqr=positive*positive*negative=negative BUT if p and q are both negative and r is positive then pqr=negative*negative*positive=positive. Not sufficient.

Answer: E.

Hope it's clear.

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Pls put ans in the spoiler option dont show up.....
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monirjewel
Pls put ans in the spoiler option dont show up.....

Done. Thank you for the suggestion.
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1 alone = p+ and q+ or p- and q-
2 alone = p+ and r- or p- and r+
alone insufficient either of them
1+2:
P+ q+ r- => negative or
p- q- r+ -> positive
so insufficient.

E.
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pqr > 0?

stmt1. pq>0 this means same sign => (+) (+) or (-) (-) for p and q but nothing about r. NS.

stmt2. q/r<0 this means differen sign => (+) (-) or (+) (-) for p and r but nothing about p. NS.

combined. you can have (+) (+) (-) for p, q, r and (-) (-) (+) for p, q, r => this gives you negative answer or positive answer. So this is not sufficient.

Answer is E
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Is pqr > 0 ?

(1) pq > 0
(2) q/r < 0


Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

This question is about an inequality. We count 1 inequality in conditions as 1 equation for inequality questions.

There are 3 variables and 0 equation. Thus the answer E is most likely.

When we consider both conditions 1) and 2) together, we have inequalities \(pq > 0\) and \(qr < 0\) which is equivalent to \(q/r < 0\).
We can't figure our \(pqr > 0\) from those inequalities.

Therefore, E is the answer.

-> For cases where we need 3 more equations, such as original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 80 % chance that E is the answer, while C has 15% chance and A, B or D has 5% chance. Since E is most likely to be the answer using 1) and 2) together according to DS definition. Obviously there may be cases where the answer is A, B, C or D.
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