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Is the range of the integers 6, 3, y, 4, 5, and x greater

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Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 25 Jun 2012, 03:03
6
36
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

62% (01:48) correct 38% (01:45) wrong based on 1820 sessions

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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 25 Jun 2012, 03:04
6
6
SOLUTION

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x. If \(x=1\) and \(y=4\) then the range=6-1=5<9 but if \(x=100\) then the range>9. Not sufficient.

(2) y > x > 3. If \(x=4\) and \(y=5\) then the range=6-3=3<9 but if \(x=100\) then the range>9. Not sufficient.

(1)+(2) From \(x > 3\) we have that the least value of \(x\) is 4, and from \(y > 3x=12\) we have that the least value of \(y\) is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Answer: C.
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 25 Jun 2012, 08:41
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1
Hi,

Range = Largest value - smallest value.

6, 3, y, 4, 5, and x, where x & y are integers

Using (1),
y>3x, if x=1, then y = 4, 5,..100....
in each case range can be 5, 6,....So, range is greater than 5. Insufficient.

Using (2),
y>x>3.
Minimum value of x = 4,
y=5,6,7... We can't say whether range is greater than 9.

Combining both statements;
\(x_{min} = 4\)
& since, y > 3x, \(y_{min}=13,\)
thus, 3, 4, 4, 5, 6, & 13 has range (13-3)=10, which is greater than 9
and on increasing x, range will also increase.

Thus, answer is (C),

Regards,
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 29 Jun 2012, 04:36
1
SOLUTION

Is the range of the integers 6, 3, y, 4, 5, and x greater than 9?

Given integers are: {3, 4, 5, 6, x, y}

(1) y > 3x. If \(x=1\) and \(y=4\) then the range=6-1=5<9 but if \(x=100\) then the range>9. Not sufficient.

(2) y > x > 3. If \(x=4\) and \(y=5\) then the range=6-3=3<9 but if \(x=100\) then the range>9. Not sufficient.

(1)+(2) From \(x > 3\) we have that the least value of \(x\) is 4, and from \(y > 3x=12\) we have that the least value of \(y\) is 13, hence the least value of the range is 13-3=10>9. Sufficient.

Answer: C.
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 27 Mar 2016, 19:25
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Here is a visual that should help.
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 03 Nov 2016, 06:49
Bunuel wrote:
Is the range of the integers 6, 3, y, 4, 5, and x greater than 9?

(1) y > 3x
(2) y > x > 3

Diagnostic Test
Question: 32
Page: 25
Difficulty: 650


pretty easy for a 700 level question...

1. x can be 1, and y can be 4 - so the answer is NO
x can be 4, and y can be 13 - so the answer is YES.
1 alone is insufficient. A and D are out.

2. y>x>3.
x can be 4, y =5 - answer is no
x can be 4, y can be 20 - answer is YES.
2 alone is not sufficient. B is out.

1+2.
x>3
y>3x
minimum value for x is 4.
minimum value for y is 13
yes, the range is greater than 9.

sufficient.
answer is C.
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 29 May 2018, 16:31
Bunuel wrote:
Is the range of the integers 6, 3, y, 4, 5, and x greater than 9?

(1) y > 3x
(2) y > x > 3


Statement One Alone:

y > 3x

Statement one is not sufficient to answer the question. For example, if x = 0, y could be 1 and the range is 6 - 0 = 6, which is less than 9. However, if x = 10, y could be 31 and the range is 31 - 3 = 28, which is greater than 9.

Statement Two Alone:

y > x > 3

Statement two is not sufficient to answer the question. For example, if x = 4, y could be 5 and the range is 6 - 0 = 6, which is less than 9. However, if x = 14, y could be 15 and the range is 15 - 3 = 12, which is greater than 9.

Statements One and Two Together:

From the two statements, we know that x > 3 and y > 3x. So the smallest integer x can be is 4 and the smallest integer y can be is 3(4) + 1 = 13. Thus the smallest range of the integers is 13 - 3 = 10, which is greater 9. Since 10 is the smallest range, any other range of the integers will be greater than 10 and hence greater than 9.

Answer: C
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 12 Sep 2018, 10:35
In the solution of these questions it is not asked to take minimum value and x and y can take any numbers so why we have solved this by taking minimum values
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Re: Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 16 Oct 2018, 00:05
2
arpitalewe wrote:
In the solution of these questions it is not asked to take minimum value and x and y can take any numbers so why we have solved this by taking minimum values


Hi arpitalewe,

Welcome to the GMAT Club!

So the logic behind trying to take the minimum permissible values for x and y is: we want to see if the minimum permissible value of y is such that range of the given set is greater than 9. If for minimum value this condition holds then for all other values it will hold as well.

Hope this solves your doubt.

Let me know if you need further clarification or if the above solutions make sense with the above logic.

Regards,
Gladi
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Is the range of the integers 6, 3, y, 4, 5, and x greater  [#permalink]

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New post 16 Oct 2018, 00:28
1
Statement 1)

y > 3x

if x = 1 then y must be at least 4 but we cannot tell any further. 6-1 = 5 > 9 no.

If x = 5 y must be at least 16. 16 - 3 = 13 > 9 yes

Insufficient.

Statement 2)

y > x > 3 we can try the x = 4 and y = 5 we get an answer 6-3 = 3 > 9 no.

Try x = 4 y = 16, 16-3 = 13 > 9 yes.

Insufficient.

Now combine (1 and 2)

If x = 4 then y at least 13 (given that we took the minimum possible value for x)

13 - 3 = 10 > 9

Try x = 10 then y at least 31

31 - 3 = 28 > 9

Sufficient. Answer choice C

arpitalewe check the above solution it might help.

Also as Gladiator59 explained that the logic is to test if the minimum value satisfies the condition (range > 9) then the maximum will satisfy it too since y > 3x

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Is the range of the integers 6, 3, y, 4, 5, and x greater   [#permalink] 16 Oct 2018, 00:28
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