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Bunuel
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Bunuel
Is the sum of a sequence of n consecutive integers even?

(1) n = 6

(2) The n digit number formed by the series is a multiple of nine.
Solution:
Pre Analysis:
  • We know sun of n consecutive integer is calculated by formula \(\frac{n}{2}(firstnumber+lastnumber)\)

Statement 1: \(n=6\)
  • Let the first number be \(a\), then the last number will be \(a+5\)\(\) because there are 6 consecutive integers: \(a, a+1, a+2, a+3, a+4, a+5\)
  • Sum of 6 consecutive integers \(=\frac{6}{2}(a+a+5)=3(2a+5)=6a+15=even+odd=odd\)
  • We see that sum of 6 consecutive integers is always odd
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: The n digit number formed by the series is a multiple of nine
  • This means the sum of the digits is a multiple of 9 which can be both even or odd
  • Thus, statement 2 alone is not sufficient


Hence the right answer is Option A
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