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18 Oct 2005, 16:35
Kudos
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N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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is there a short cut for this?
pls show working
pls show working
Archived Topic
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18 Oct 2005, 17:04
Kudos
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C
1/sqrt(x+y)
pick x=16 and y=9
sq(x+y) = 5; sq(x)+sq(y) = 7, sq(x)-sq(y) = 1
Bring ii and iii to have same denominator as sq(x+y) -> by dividing the numerator and den. by sq(x+y).
Plug values to see if Nummerator is greater than 1 -> only ii is greater
multiply i by sq(x+y) on both N and D and do the same as above.
Only ii must be greater (C)
1/sqrt(x+y)
pick x=16 and y=9
sq(x+y) = 5; sq(x)+sq(y) = 7, sq(x)-sq(y) = 1
Bring ii and iii to have same denominator as sq(x+y) -> by dividing the numerator and den. by sq(x+y).
Plug values to see if Nummerator is greater than 1 -> only ii is greater
multiply i by sq(x+y) on both N and D and do the same as above.
Only ii must be greater (C)
18 Oct 2005, 17:24
Kudos
Bookmarks
fresinha12
hey fresinha
Another quick way would be to cross multiply the 1/Sqrt(x+y) with the choices
1 if you cross multiply then choice 1 would be x + y and 2x we don't know for certain if x + y is greater than 2x they might be equal for all we know. Eliminate
2. if we cross multiply here we would get
x*sqrt(y) + y*sqrt(x) and x + y
if both x and y are positive then choice 2 is definitely larger Keep!
3. if we cross mulitiply here we get
x*sqrt(y) - y*sqrt(x) and x + y since we know from choice that choice two is greater than x + y we know that choice 3 is definitely less than x + y. Eliminate
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
