|x-v| < 8

First, the easy answer.

Solution two:Plug in numbers. V is +4 or -4. X is +6 or -6.

Therefore, we have four combinations:

|4-6| = 2

|-4-6| = 10

Already, we can tell that |v-x| could be > OR < 8.

So, two alone cannot solve.

Now, it gets more fun:|x-v| < 8 must be broken into two equations thanks to the inequality.

We have:

a. x-v < 8

b. -(x-v) > 8 -- note the flip in inequality*.

With these two solutions.

I. v and x are integers: this only tells us x and v are not decimal numbers. Not that useful in my opinion.

If x is 20 and v is 2, x-v is not less than 8 and -(x-v) is not greater than 8.

If x is 2 and v is 20, x-v IS less than 8 and -(x-v) IS greater than 8.

So one alone cannot work.

How about both together?Well, when we tried solution two alone, we used integers anyways. Answer two essentially tells you the numbers are integers.

I would say e, neither answer alone nor together.

*Now, you really didn't need to know about the 'flip the equality' part above for this question, but I find that it is a useful thing to know when dealing with absolute numbers in equalities...

_________________

________________________________________________________________________

Andrew

http://www.RenoRaters.com