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Is x < 0? (1) x + 2 > 0 (2) 2x > 3x

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Joined: 02 Sep 2009
Posts: 49364
Is x < 0? (1) x + 2 > 0 (2) 2x > 3x  [#permalink]

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New post 03 Dec 2017, 06:27
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

82% (00:27) correct 18% (00:42) wrong based on 51 sessions

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Re: Is x < 0? (1) x + 2 > 0 (2) 2x > 3x  [#permalink]

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New post 03 Dec 2017, 06:58
Bunuel wrote:
Is x < 0?

(1) x + 2 > 0
(2) 2x > 3x


Given: is x < 0:
(1) x+2>0; x=-1, then (-1)+2>0, true. x=10, then (10)+2>0, also true; not suf.
(2) 2x>3x; the only possible solution for this is if x<0; sufficient.
(B) is the answer.
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Re: Is x < 0? (1) x + 2 > 0 (2) 2x > 3x  [#permalink]

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New post 03 Dec 2017, 12:06
Bunuel wrote:
Is x < 0?

(1) x + 2 > 0
(2) 2x > 3x



(1) x + 2 > 0 or x > -2
x is greater than -2 but it could lie between -2 and 0 (so negative) or be equal to 0 or greater than 0. Insufficient.

(2) 2x > 3x or 2x-3x > 0 or -x> 0
Multiplying both sides by -1, we get x < 0. Sufficient.

Hence B answer
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Re: Is x < 0? (1) x + 2 > 0 (2) 2x > 3x &nbs [#permalink] 03 Dec 2017, 12:06
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