Bunuel
Is \(x > 0\)?
(1) \(x^3+x^2+x<0\)
(2) \(x^2<1\)
Given : A variable x that can either be an integer or a positive / negative fraction (as x is not specified)
To determine : If x > 0
Note: Definitive yes or definitive no to be obtained for x>0
Statement A : - We are given that x^3 + x^2 + x< 0.
- Factorizing this, x*(x^2+x+1)<0
- This leaves us with two options, x<0 & (x^2+x+1) >0 (Case 1) OR x>0 & (x^2+x+1)<0 (Case 2)
- Case 1 seems good to go (For ex : x=-1 satisfies, x=-1/2 also satisfies and therefore, x clearly < 0)
- Case 2 fails because there is no value of x >0 for which x^2+x+1<0
- Therefore, case 1 stays valid and we definitely know x>0.
Statement A is sufficient*Automatically Eliminate Options C & E*Statement B : - We are given that x^2<1
- Therefore taking square roots on both sides, x clearly lies between 1 & -1
=> For example, x can be 1/2 (here x>0) or -1/3 (here x<0)
=> We do not have a definitive yes or a definitive no for x>0 and therefore,
Statement B is not sufficient*Eliminate Options B & D*=> OA : A is the right Answer choice