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arjtryarjtry
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 03:39
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Is \(|x - 1| 0\)



* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

i thougth taht A is OK. what is wrong with A?



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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 05:39
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arjtryarjtry
Is \(|x - 1| < 1\) ?

1. \((x - 1)^2 <= 1\)
2. \(x^2 - 1 > 0\)



* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

i thougth taht A is OK. what is wrong with A?
Show more

IMO C is the ans, Will gv a detailed explanation if this is correct.
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 07:27
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arjtryarjtry
Is \(|x - 1| < 1\) ?

1. \((x - 1)^2 <= 1\)
2. \(x^2 - 1 > 0\)



* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

i thougth taht A is OK. what is wrong with A?
Show more

The answer is C.

Question: is |x - 1| < 1?

(1) \((x - 1)^2 <= 1\)
((x - 1)^2)^1/2 <= 1^1/2 ----- ^1/2
|x - 1| <= 1 ----- ((a^2)^1/2) = |a|
We can notice that it is very similar to the question stem but 1 is included here so INSUFF

(2) x^2 - 1 > 0
(x-1)(x+1) > 0
Therefore, x < -1 or x > 1. Clearly INSUFF

(1) + (2); Since (2) force number 1 out of |x - 1| <= 1
SUFF
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 07:49
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arjtryarjtry
Is \(|x - 1| < 1\) ?

1. \((x - 1)^2 <= 1\)
2. \(x^2 - 1 > 0\)



* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

i thougth taht A is OK. what is wrong with A?
Show more


Looks like you missed "<=" part.
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 08:12
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devilmirror
arjtryarjtry
Is \(|x - 1| < 1\) ?

1. \((x - 1)^2 <= 1\)
2. \(x^2 - 1 > 0\)



* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

i thougth taht A is OK. what is wrong with A?

The answer is C.

Question: is |x - 1| < 1?

(1) \((x - 1)^2 <= 1\)
((x - 1)^2)^1/2 <= 1^1/2 ----- ^1/2
|x - 1| <= 1 ----- ((a^2)^1/2) = |a|
We can notice that it is very similar to the question stem but 1 is included here so INSUFF

(2) x^2 - 1 > 0
(x-1)(x+1) > 0
Therefore, x < -1 or x > 1. Clearly INSUFF

(1) + (2); Since (2) force number 1 out of |x - 1| <= 1
SUFF
Show more

x^2 - 1 > 0

means x ^ 2 > 1

means x is > 1 or x > -1 How come you are getting x< -1 above?
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 08:20
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icandy
devilmirror
arjtryarjtry
Is \(|x - 1| < 1\) ?

1. \((x - 1)^2 <= 1\)
2. \(x^2 - 1 > 0\)



* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
* Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
* BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
* EACH statement ALONE is sufficient
* Statements (1) and (2) TOGETHER are NOT sufficient

i thougth taht A is OK. what is wrong with A?

The answer is C.

Question: is |x - 1| < 1?

(1) \((x - 1)^2 <= 1\)
((x - 1)^2)^1/2 <= 1^1/2 ----- ^1/2
|x - 1| <= 1 ----- ((a^2)^1/2) = |a|
We can notice that it is very similar to the question stem but 1 is included here so INSUFF

(2) x^2 - 1 > 0
(x-1)(x+1) > 0
Therefore, x < -1 or x > 1. Clearly INSUFF

(1) + (2); Since (2) force number 1 out of |x - 1| <= 1
SUFF

x^2 - 1 > 0

means x ^ 2 > 1

means x is > 1 or x > -1 How come you are getting x< -1 above?
Show more

(x-1)(x+1) > 0

means (x>1 and x>-1 ) or (x<1 and x<-1)
--> x>1 or x<-1
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 06 Sep 2008, 20:44
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lx-1l <1 means 0<x< 2

(x-1)^2 <= 1 means 0 <= x <= 2 >>>> insuff when x = 0 or x = 2 (A)
x^2 - 1 > 0 means -1 < x or x > 1 >>> insuff (B)

(A) + (B) >>> 1 < x <= 2 >>> insuff when x =2

Therefore: My answer is E
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Is |x - 1| < 1 ? 1. (x - 1)^2 <= 1 2. x^2 - 1 27 Nov 2009, 01:40
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answer must be E

1> gives us range 0 gives us range x 1

combining both we are left wit possibility that 1 < x <=2



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!