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TeHCM
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question:

with absolute signs, to find the positive value, we simply drop the absolute signs and solve for x. as in stmt 1, x = 3

so, then, how do we find the negative value of |x+1| = 2|x-1| ? what are the steps?
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C aswell.

x=1/3 or x=3, therefore taking both statments x=1/3 suff.
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Its C.

With |x+1| = 2|x-1|

we have the following cases:
(after solving for x)
1. x+1 >= 0, x-1 >= 0 ==> x =3
2. x+1 >= 0, x-1 x = 1/3
3. x+1 = 0 ==> No Soln.
4. x+1 x = 3

Without (2) |x-3| != 0, we have two solutions.



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