GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 10 Dec 2018, 19:20

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in December
PrevNext
SuMoTuWeThFrSa
2526272829301
2345678
9101112131415
16171819202122
23242526272829
303112345
Open Detailed Calendar
• ### Free lesson on number properties

December 10, 2018

December 10, 2018

10:00 PM PST

11:00 PM PST

Practice the one most important Quant section - Integer properties, and rapidly improve your skills.
• ### Free GMAT Prep Hour

December 11, 2018

December 11, 2018

09:00 PM EST

10:00 PM EST

Strategies and techniques for approaching featured GMAT topics. December 11 at 9 PM EST.

# Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 51072
Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)  [#permalink]

### Show Tags

17 Apr 2018, 00:04
00:00

Difficulty:

25% (medium)

Question Stats:

79% (01:29) correct 21% (01:47) wrong based on 71 sessions

### HideShow timer Statistics

Is $$x > 1$$?

(1) $$x^2 + x + 2 > 8$$

(2) $$8(x – 4) > 4(x – 2)$$

_________________
examPAL Representative
Joined: 07 Dec 2017
Posts: 841
Re: Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)  [#permalink]

### Show Tags

17 Apr 2018, 01:29
Bunuel wrote:
Is $$x > 1$$?

(1) $$x^2 + x + 2 > 8$$

(2) $$8(x – 4) > 4(x – 2)$$

Instead of solving explicitly, we'll look for simple numbers that contradict the given statements.
This is an Alternative approach.

(1)
Let's try a number that gives us a YES. If we make x very large, say x = 100, then 100^2+100+2 is definitely larger than 8.
Not let's try to contradict this by getting a NO. If we make x very small, say x = -100 then (-100)^2 - 100 + 2 is 10,000 -100 + 2 which is also larger than 8.
We have found both x > 1 and x < 1 which gives a correct statement (1) so this is not enough.
Insufficient!

(2)
Since it's hard to guess what numbers to pick, we'll first simplify a bit.
8x - 32 > 4x - 8
4x > 24
x > 6.
In this case, there is no need to pick numbers at all!
Sufficient.

(B) is our answer.
_________________
Manager
Joined: 28 Nov 2017
Posts: 145
Location: Uzbekistan
Re: Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)  [#permalink]

### Show Tags

17 Apr 2018, 03:25
Bunuel wrote:
Is $$x > 1$$?

(1) $$x^2 + x + 2 > 8$$

(2) $$8(x – 4) > 4(x – 2)$$

The first statement tells us that
$$x^2 + x + 2 > 8$$ or
$$x^2 + x - 6 > 0$$,
$$(x+3)(x-2)>0$$.
So, from this, we know that $$x>2$$ and $$x<-3$$. Insufficient.

If we solve the second inequality, then we end up with $$x>6$$ which is sufficient.

Answer: B
_________________

Kindest Regards!
Tulkin.

Intern
Joined: 11 Mar 2015
Posts: 35
Re: Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)  [#permalink]

### Show Tags

17 Apr 2018, 04:00
1) From 1 we get X>2 and X<-3.
2) From 2 we get X>6.

Hence B is my answer.
Intern
Joined: 08 Jul 2018
Posts: 22
Location: India
Concentration: General Management, Marketing
GPA: 4
Re: Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)  [#permalink]

### Show Tags

14 Aug 2018, 06:20
Tulkin987 wrote:
Bunuel wrote:
Is $$x > 1$$?

(1) $$x^2 + x + 2 > 8$$

(2) $$8(x – 4) > 4(x – 2)$$

The first statement tells us that
$$x^2 + x + 2 > 8$$ or
$$x^2 + x - 6 > 0$$,
$$(x+3)(x-2)>0$$.
So, from this, we know that $$x>2$$ and $$x<-3$$. Insufficient.

If we solve the second inequality, then we end up with $$x>6$$ which is sufficient.

Answer: B

Hi,

Please explain

How did you get from
x+3>0 to x<-3

I couldn't understand it.
Director
Status: Learning stage
Joined: 01 Oct 2017
Posts: 931
WE: Supply Chain Management (Energy and Utilities)
Re: Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)  [#permalink]

### Show Tags

14 Aug 2018, 08:58
Bunuel wrote:
Is $$x > 1$$?

(1) $$x^2 + x + 2 > 8$$

(2) $$8(x – 4) > 4(x – 2)$$

Question stem:- Is x>1 ?

St1:- $$x^2 + x + 2 > 8$$
Or, $$x^2+x-6>0$$
Or, $$x^2-2x+3x-6>0$$
Or, $$x(x-2)+3(x-2)>0$$
Or, $$\left(x-2\right)\left(x+3\right)>0$$
Cut off points:- x=2, -3
Applying wavy-curve method(figure enclosed), the region of the curve above horizontal axis(since the product is positive),
x<-3 , x>2
So, x may or mayn't be greater than 1.
Insufficient.

St2:- $$8(x – 4) > 4(x – 2)$$
Or, 8x-32>4x-8
Or, 8x-4x>-8+32
Or, 4x > 24
Or, $$x> \frac{24}{4}$$
Or, x > 6
Sufficient.

Ans. (B)
Attachments

wavy.JPG [ 44.31 KiB | Viewed 305 times ]

_________________

Regards,

PKN

Rise above the storm, you will find the sunshine

Re: Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2) &nbs [#permalink] 14 Aug 2018, 08:58
Display posts from previous: Sort by

# Is x > 1? (1) x^2 + x + 2 > 8 (2) 8(x – 4) > 4(x – 2)

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.