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31 Jan 2023, 07:13
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
67% (01:47) correct
33%
(01:36)
wrong
based on 30
sessions
History
Date
Time
Result
Not Attempted Yet
11 Feb 2023, 12:10
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Bunuel
(1) \(x<√x<y\)
This gives a definite range for \(x\) i.e. \(x< 1\) but tells us nothing about \(y \). e.g.
\(x= \frac{1}{4}\), \( \sqrt x = {\frac{1}{2}} , y = {\frac{1}{1.5}}\) NO to the stem.
\(x= \frac{1}{4}\), \(\sqrt x = {\frac{1}{2}},\) \(y = 2 \) Yes to the stem.
Note: \(x\) can only be positive because it is under square root.
INSUFF.
(2) \(x<√y<y\)
This gives a definite range for \(y\) i.e. \(y> 1\) but tells us nothing about \(x\) e.g.
\(x= 1.5,\sqrt y = 2, y= 4, \) NO to the stem.
\(x= .5, \sqrt y = 2, y= 4, \) Yes to the stem.
Note: \(y\) can only be positive because it is under square root.
INSUFF.
1+2
From 1 we know \(x< 1\)
From 2 we know \(y >1\)
Thus \(x< 1< y\)
SUFF.
Ans C
Hope it's clear.
12 Feb 2023, 07:54
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Bunuel
There are two parts to the question asked
- Is x less than 1
- Is y greater than 1
Statement 1
(1) \(x<√x<y\)
The presence of √x suggests that x is positive, x < √x when x < 1. Let's plot the information over a number line
--- 0 ----- x ----- √x -- y -- 1 ----- y -------------
Based on the information given in statement 1, we can have multiple positions of y.
y can be greater than √x but less than 1 or it is greater than 1. Hence we don't have a conclusive answer. The statement is not sufficient and we can eliminate A and D.
Statement 2
(2) \(x<√y<y\)
As √y < y, y must be greater than 1
--- 0 -------------- x ----------------- 1 --- x ------ √y ------------ y ------
Based on the information given in statement 1, we can have multiple positions of x.
x can be greater than 1 but less than √y or it can be less than 1. Hence we don't have a conclusive answer. The statement is not sufficient and we can eliminate B.
Combined
We know that x < 1 from statement 1 and y > 1 from statement 2.
The statement combined helps us answer the question.
Option C
