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Amit05
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 06:33
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Is x > 3 ?

1. (x-3)(x-2)(x-1) > 0
2. x > 1


Could anyone please explain ?



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alrussell
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 09:23
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Amit05
Is x > 3 ?

1. (x-3)(x-2)(x-1) > 0
2. x > 1


Could anyone please explain ?
Show more


I make it C I think.. though I'd like to see the OA.

Statement 1 - if x is 1, 2, 3, or 4, the statement is incorrect, thus, if x is positive, then it must be above 3. However, if x is negative, then it may perhaps work. if x is -2, then the statement is correct.

Statement 2 - on it's own is insufficient - x can be anywhere between 1 and 3...

Together though it tells us x is a positive number above 3...

I think...
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GMAT TIGER
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 09:34
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Amit05
Is x > 3 ?

1. (x-3)(x-2)(x-1) > 0
2. x > 1


Could anyone please explain ?
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A. nice one as x>3. if not (x-3)(x-2)(x-1) will be either 0 or -ve.
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Ferihere
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 09:42
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Amit05
Is x > 3 ?

1. (x-3)(x-2)(x-1) > 0
2. x > 1


Could anyone please explain ?
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Clearly A, just draw a number line and everything will be clear
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KillerSquirrel
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 09:42
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Why are you all assuming that x is an integer ?

Is x > 3 ?

statement 1

(x-3)(x-2)(x-1) > 0

This will be true when:

(x-3), (x-2) and (x-1) are positive (i.e. x=4 {1,2,3})

(x-1) is positive and (x-2), (x-3) are negative (i.e x=1.5 {0.5,-1.5,-2.5}

insufficient

statement 2

clearly insufficient

both statements

still insufficient

statement 2 doesn't add any new information

so the answer is (E)

:)
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jimmyjamesdonkey
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 16:43
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Killer, I see your point but still saying A.

I forget the rule, but if you a bunch of #s together is equal to 0, then you can set each one individually to zero and solve. Something like that. I did the following

A.

x-3>0
x-2>0
x-1>0

X > 3 suff.

Killer, Also you said it yourself. You forget this is a yes/no question....Statement 1 is true when we have integers. That is how we knows it is a positive.

B. x>1 not suff.
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 17:52
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jimmyjamesdonkey
Killer, I see your point but still saying A.

I forget the rule, but if you a bunch of #s together is equal to 0, then you can set each one individually to zero and solve. Something like that. I did the following

A.

x-3>0
x-2>0
x-1>0

X > 3 suff.

Killer, Also you said it yourself. You forget this is a yes/no question....Statement 1 is true when we have integers. That is how we knows it is a positive.

B. x>1 not suff.
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I dont follow. E seems right... I think KS is correct no?

If X is 1.5, then we end up with -1.5 x -0.5 x 0.5 = 0.325 so answer is no

If X is 4, then we end up with 1 x 2 x 3 = 6 so answer is yes.

Thus Statement 1 is insuff.

As KS said - both numbers also fit within statement 2. 1.5 > 1 as is 6.

Thus E.
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Is x > 3 ? 1. (x-3)(x-2)(x-1) > 0 2. x > 1 17 Nov 2007, 22:15
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KillerSquirrel
Why are you all assuming that x is an integer ?

Is x > 3 ?

statement 1

(x-3)(x-2)(x-1) > 0

This will be true when:

(x-3), (x-2) and (x-1) are positive (i.e. x=4 {1,2,3})

(x-1) is positive and (x-2), (x-3) are negative (i.e x=1.5 {0.5,-1.5,-2.5}

insufficient

statement 2

clearly insufficient

both statements

still insufficient

statement 2 doesn't add any new information

so the answer is (E)

:)
Show more


You Rock man .. Got it. I had that integer thing in my mind but was to lazy to give it a try ..



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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