apoorvasrivastva wrote:

skpMatcha wrote:

the answer is 'B'

\(((x-3)^2)^0.5 = 3-x ?\)

statement 1: NOT SUFF

it just says x<>3, what abt x > 3 the inequality holds good

Statement 2: the given equality holds good for all negative values

-x|x|> 0

x>0 --> -x^2 > 0 -> a negative number cant be > 0 so x cant be > 0

x < 0 --> x2 > 0 --> yes so x is negative

for all negative values this holds good.

hence B

well can the question be written as is |x-3| = 3-x?

Thats what the question is.

[(x-3)^2]^0.5 = (3-x) ?

Irrespective of x's value, (x-3)^2 is always +ve. Sqrt of (x-3)^2 is always +ve (x - 3).

Therefore ((x-3)^2)^0.5 = |x - 3|. Hence |x - 3| = (3-x) ?

For example: x = -4, 0 , 1, 5

If x = -4, [(x-3)^2]^0.5 = [(-4-3)^2]^0.5 = [(-7)^2]^0.5 = (49)^0.5 = 7, which is equal to |-4 - 3| = |7| = 7

If x = 0, [(x-3)^2]^0.5 = [(-0-3)^2]^0.5 = [(-3)^2]^0.5 = (9)^0.5 = 3, which is equal to |0 - 3|= |3| = 3

If x = 1, [(x-3)^2]^0.5 = [(1-3)^2]^0.5 = [(-2)^2]^0.5 = (4)^0.5 = 2, which is equal to |1 - 3| = |2| = 2

If x = 5, [(x-3)^2]^0.5 = [(5-3)^2]^0.5 = [(2)^2]^0.5 = (4)^0.5 = 2, which is equal to |5 - 3| = |2| = 2

_________________

Verbal: http://gmatclub.com/forum/new-to-the-verbal-forum-please-read-this-first-77546.html

Math: http://gmatclub.com/forum/new-to-the-math-forum-please-read-this-first-77764.html

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

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