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jabhatta2
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avigutman
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GMAT 3: 770 Q50 V45
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jabhatta2
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thanks so much avigutman for responding.

I think the way to re-phrase the question stem specifically is the following way

Is LHS = RHS ?

From the graph
if x cordinate is
+ 6 - answer to question is No
+ 5 - answer to question is No
+ 4 - answer to the question is NO
+ 3 - answer to the question is Yes
+ 2 - answer to the question is Yes
+ 1 - answer to the question is Yes
+ 0 - answer to the question is Yes
- 1 - answer to the question is Yes
- 2 - answer to the question is Yes
- 3 - answer to the question is Yes
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^^ when it comes to S2 -- the answer is always "Yes" as the lines are always overlapping
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[quote="esledge"]
So for this question: Is sqrt[(x-3)^2] = 3-x?

Rephrase to: Is |x-3| = 3-x?

If stuff in the absolute value sign is positive or zero, this becomes:
Is x-3 = 3-x?
Is 2x = 6?
Is x = 3?

If stuff in the absolute value sign is negative, this becomes:
Is -(x-3) = 3-x?
Is -x+3 = 3-x?
The answer is yes for all x, but remember this was just "all x" such that x-3 was negative, or x < 3: So we ask "Is x < 3?"

Can you please explain me how did you get to the conclusion that x<3. When I consider -
Is -(x-3) = 3-x? I get the answer as x=0. Then if i substitute these back in the equation we still get both of them as possible solutions. Why didn't you think that this equation has two solutions x=0, x=3. I wanted to understand the thought process behind getting to x<3
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