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Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0

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Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 02:23
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E

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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 02:37
E

From st1 we get x>-5 or x>5. Two values are possible. Hence insufficient.

From st2 2x+7>0

X>-3.5 x can be either greater than 5 or less than 5. Hence insufficient
Combining still x can be greater than or less than 5. Hence insufficient


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Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 04:27
Bunuel wrote:
Is x > 5 ?

(1) x^2 > 25
(2) 2x + 7 > 0


St.1: x > 5 or x < -5 ; ins
St.2: 2x + 7 > 0 , x > -3.5 ; ins

St.1&2: If x > -5 = -6 and we plug it into St.2: "2(-6) + 7 < 0" the condition becomes false. So, x > 5 answers is (C).

Last edited by exc4libur on 13 Nov 2017, 11:36, edited 1 time in total.

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Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 08:40
exc4libur wrote:
Bunuel wrote:
Is x > 5 ?

(1) x^2 > 25
(2) 2x + 7 > 0


St.1: x > 5 or x > -5 ; ins
St.2: 2x + 7 > 0 , x > -3.5 ; ins

St.1&2: If x > -5 = -6 and we plug it into St.2: "2(-6) + 7 < 0" the condition becomes false. So, x > 5 answers is (C).


hey i arrived at C too
but i think there is some discrepancy in above solution [Please correct me if I am wrong]

St1 : x^2 > 25
means x>5 or x < -5 ...... but no definite ans
[To check the validity
i.) x>5 assume x=6 , 6^2>25 OK
ii.) x<-5 assume x=-6 (-6)^2 >25 OK -6 <-5
]


St2 : 2x + 7 > 0 , x > -3.5

Combining , x>5 as x<-5 does not satisfy the 2nd condtn
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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 11:38
Hi ak,
Could you be more specific? Sorry.

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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 12:47
Is x > 5 ?

(1) x^2 > 25
(2) 2x + 7 > 0

============

1) x^2 > 25
X > 5 and X < -5
not sufficient

2) 2x + 7 > 0
x > - 3.5
not sufficient

Combine 1 & 2
let us say X = -2 , satisfy X > -3.5 but doesn't satisfy X > 5 or X < -5
let us say X = 6 , satisfy both X > -3.5 and X > 5

Answer - E.

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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 13 Nov 2017, 23:06
exc4libur wrote:
Hi ak,
Could you be more specific? Sorry.


Statement 1 : x^2 > 25
Means, either x>5 or x<-5

So, we cannot be 100% sure of whether x>5.
Hence, this statement is insufficient.

Statement 2 : 2x+7>0
which is equivalent to 2x > 7
or further, x > 3.5
So, this can give us any value between 3.6 to infinity.
Hence, we cannot be 100% sure of whether x>5.
Again, INSUFFICIENT

So, combining, we know from st-1 that x>5 or x<-5
But st-2 says, x>3.5

So, the possibility that x<-5 is NOT valid.

Hence, we are left with, x>3.5 and x>5, so obviously, x>5
and we answer the question with a definite YES.

So, option C
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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 14 Nov 2017, 02:12
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From 1: x^2 >25 => X>5 or X<-5 => not suff

From 2: 2x+7>0 => X>-3/5 => not suff

From 1 and 2, X>5 => Suff. Answer C

Please kudo if it's help.

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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0 [#permalink]

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New post 14 Nov 2017, 20:35
IMO C

1> 5>X and X <-5 not sufficient

2> 2X > 7 --> x > -3.5 not sufficient

combining both X>5
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Re: Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0   [#permalink] 14 Nov 2017, 20:35
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