Is x > 5 ? (1) x^2 > 25 (2) 2x + 7 > 0

hey i arrived at C too
but i think there is some discrepancy in above solution [Please correct me if I am wrong]

St1 : x^2 > 25
means x>5 or x < -5 ...... but no definite ans
[To check the validity
i.) x>5 assume x=6 , 6^2>25 OK
ii.) x<-5 assume x=-6 (-6)^2 >25 OK -6 <-5
]


St2 : 2x + 7 > 0 , x > -3.5

Combining , x>5 as x<-5 does not satisfy the 2nd condtn

Hi ak,
Could you be more specific? Sorry.

Is x > 5 ?

(1) x^2 > 25
(2) 2x + 7 > 0

============

1) x^2 > 25
X > 5 and X < -5
not sufficient

2) 2x + 7 > 0
x > - 3.5
not sufficient

Combine 1 & 2
let us say X = -2 , satisfy X > -3.5 but doesn't satisfy X > 5 or X < -5
let us say X = 6 , satisfy both X > -3.5 and X > 5

Answer - E.

Statement 1 : x^2 > 25
Means, either x>5 or x<-5

So, we cannot be 100% sure of whether x>5.
Hence, this statement is insufficient.

Statement 2 : 2x+7>0
which is equivalent to 2x > 7
or further, x > 3.5
So, this can give us any value between 3.6 to infinity.
Hence, we cannot be 100% sure of whether x>5.
Again, INSUFFICIENT

So, combining, we know from st-1 that x>5 or x<-5
But st-2 says, x>3.5

So, the possibility that x<-5 is NOT valid.

Hence, we are left with, x>3.5 and x>5, so obviously, x>5
and we answer the question with a definite YES.

So, option C

From 1: x^2 >25 => X>5 or X<-5 => not suff

From 2: 2x+7>0 => X>-3/5 => not suff

From 1 and 2, X>5 => Suff. Answer C

Please kudo if it's help.

IMO C

1> 5>X and X <-5 not sufficient

2> 2X > 7 --> x > -3.5 not sufficient

combining both X>5

Problem Statement x>5? we need a definite YES or a definite NO
Statement 1->
x^2>25
Let's try to invalidate the expression by plugging in some values from the range mentioned in problem statement;
x=6 -> x^2=36 ->
Hence, x>5 and YES
But if x=-6?
x^2=36; Statement 1 is sufficed but we get a NO for problem statement
Hence Statement 1 alone is not sufficient.

Statement 2->
2x+7>0
Clearly it is not sufficient alone, let's consider both the statements now;

From the statement 1 we know that negative values are the ones that causes problem in case of squaring, let's check for those cases only as we know that it would always be true for all the positive values of x
Let's take x=-6 and statement 2 falls for x=-6 as -12+7=-5 which is not positive, hence we get the surety here that x is not less than -5

Thus we can say that by combining both the statements, we can arrive at our answer.

OPTION C