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Is |x-6| > 5? 1. x is an integer 2. x^2 < 1

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Is |x-6| > 5? 1. x is an integer 2. x^2 < 1 [#permalink]

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New post 29 Dec 2008, 20:34
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is |x-6| > 5?


1. x is an integer
2. x^2 < 1

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 29 Dec 2008, 22:19
should be E

|x-6| > 5 can be written as x>11 and x<1 on the number line

1) x is an integer - INSUFF - coz X can be any number.
2) x^2 < 1 which can be written as |X| < 1 --->In a number line X<1 and X>-1 - INSUFF

Combining both inSUFF

OA?

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 30 Dec 2008, 02:49
From stmt2:
-1 < x < 1
or, -7 < x-6 < -5
or, 5 < |x-6| < 7

Hence, answer should be B.

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 30 Dec 2008, 06:55
OA - B.

scthakur - could you please explain statement b in detail. Thanks!

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 30 Dec 2008, 22:08
Hi scthakur can u please explain your answer in more detail.

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 30 Dec 2008, 22:59
From stmt2:
x^2 < 1, this means, -1 < x < 1
We need to compare (x-6), hence, subtract 6 from all the sides of the above inequality.
Thus, (-1-6) < (x-6) < (1-6)
or, -7 < (x-6) < -5

That means, absolute value of (x-6) will be between 5 and 7
i.e. 5 < |x-6| < 7

And this clearly explains that |x-6| > 5. Hence, sufficient.

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 30 Dec 2008, 23:06
scthakur wrote:
From stmt2:
x^2 < 1, this means, -1 < x < 1
We need to compare (x-6), hence, subtract 6 from all the sides of the above inequality.
Thus, (-1-6) < (x-6) < (1-6)
or, -7 < (x-6) < -5

That means, absolute value of (x-6) will be between 5 and 7
i.e. 5 < |x-6| < 7

And this clearly explains that |x-6| > 5. Hence, sufficient.


so silly of me why couldn't i get this........
anyways thanks a lot

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 31 Dec 2008, 13:03
vksunder wrote:
Is |x-6| > 5?

1. x is an integer
2. x^2 < 1


(x^2<1) and (x<1), which is not provided in the question, are two entirely different things but both are/would be sufficient to answer the question if x<1 were also provided as supplimentary information.

(x^2<1) has limits but (x<1) has no limit.
In (x^2<1), x is > -1 but < 1.
In (x<1), x could have any value smaller than 1.
So B is suff.
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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 31 Dec 2008, 13:51
I agree, it is B

I'd strongly recommend reading this http://www.manhattangmat.com/strategy-s ... -value.cfm for people having trouble with absolute value. It really helped me.

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Re: Absolute Value - Could someone please explain this problem [#permalink]

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New post 03 Jan 2009, 17:29
vksunder wrote:
Is |x-6| > 5?


1. x is an integer
2. x^2 < 1


|x-6| > 5

If we consider x-6 to be +ve we get x > 11. If we consider x -ve we get x <1

so the Q is 11<x<1 ??

Clearly B says that x is +ve or -ve fraction or 0, all of those do not lie between 11 and 1

Hence B is suff

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Re: Absolute Value - Could someone please explain this problem   [#permalink] 03 Jan 2009, 17:29
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