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# Is x+y>0? 1). x/x+y>0 2). y/x+y>0 From stem 1

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Senior Manager
Joined: 05 Jun 2008
Posts: 294
Is x+y>0? 1). x/x+y>0 2). y/x+y>0 From stem 1 [#permalink]

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20 Sep 2008, 12:01
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Is x+y>0?
1). x/x+y>0
2). y/x+y>0

From stem 1 X+Y<X hence y<0
From Stem 2 X+Y<Y hence X<0
So both put together are sufficient.... am i doing it correctly??
Senior Manager
Joined: 31 Jul 2008
Posts: 280

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20 Sep 2008, 12:55
should be E .. i thnk

as one cannot deduce that x+y > OR < (x OR y)

as per me :

x/x+y > 0 can mean either x and (x+y) both are positive or both are negative

similalry for y/x+y

combining both too ,, i dnt think we can conclude anything
VP
Joined: 05 Jul 2008
Posts: 1373

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20 Sep 2008, 13:01
stallone wrote:
should be E .. i thnk

as one cannot deduce that x+y > OR < (x OR y)

as per me :

x/x+y > 0 can mean either x and (x+y) both are positive or both are negative

similalry for y/x+y

combining both too ,, i dnt think we can conclude anything

Exactly, with inequalities we cannot multiply or cancel out num/den unless we know if some thing is +ve or -ve

My pick is E as well.
VP
Joined: 30 Jun 2008
Posts: 1019

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20 Sep 2008, 13:23
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vivektripathi wrote:
Is x+y>0?
1). x/x+y>0
2). y/x+y>0

From stem 1 X+Y<X hence y<0
From Stem 2 X+Y<Y hence X<0
So both put together are sufficient.... am i doing it correctly??

We can't say for sure that X > X+Y or Y > X+Y. Just because X is in the numerator does not mean it is greater than the denominator. 2/3 >0 and 3/2 is also > 0

What we can surely say is x+y is NOT zero.

(1) Both X and X+Y are of same sign. But unless we know X < 0 or >0 we cant determine if X+Y is >0 or <0. not suff

(2) same as (1). not suff

Combined, Also not suff

I go with E
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VP
Joined: 17 Jun 2008
Posts: 1325

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20 Sep 2008, 23:31
vivektripathi wrote:
Is x+y>0?
1). x/x+y>0
2). y/x+y>0

From stem 1 X+Y<X hence y<0
From Stem 2 X+Y<Y hence X<0
So both put together are sufficient.... am i doing it correctly??

1)says x>0 means x+y>0 or x<0 means x+y<0 cant say x+y <0 or >0
2)says y>0 means x+y>0 or y<0 means x+y<0 cant say x+y <0 or >0

combining both :
x<0,y<0 => x+y<0 and x>0,y>0 and x+y>0 hence still not able decide x+y sign hence IMO E
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Re: DS - Inequalities   [#permalink] 20 Sep 2008, 23:31
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