Last visit was: 19 Nov 2025, 14:59 It is currently 19 Nov 2025, 14:59
Home
GMAT
Messages
Tests
Schools
Events
Rewards
Chat
My Profile
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
kaitibruck
User avatar
Joined: 24 Sep 2006
Last visit: 07 Dec 2006
Posts: 7
Posts: 7
Kudos: 0
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 04:38
Kudos
Add Kudos
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

History

Date
Time
Result
Not Attempted Yet
Is X>Y ?

1) X+Y>0
2) y^x<0



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
keeeeeekse
User avatar
Joined: 12 Sep 2006
Last visit: 12 Oct 2007
Posts: 43
Own Kudos:
6
Posts: 43
Kudos: 6
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 06:48
Kudos
Add Kudos
Bookmarks
Bookmark this Post
should be C

(1) it does not give us any information about X and Y individually so INSUFF

(2) it could go either way, we know that Y is negative, but X could be greater or smaller so also INSUFF

combining both, we know that Y is negative and in order for (1) to be true, X must be greater and must be positive
User avatar
Fig
User avatar
Joined: 01 May 2006
Last visit: 02 Feb 2025
Posts: 1,031
Own Kudos:
253
Posts: 1,031
Kudos: 253
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 07:54
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(C) as well :)

Stat 1 : x+y >0
o if x=y=1, x+y=2 > 0
o if x=2 and y=1, x+y=3 > 0

INSUFF

Stat 1 : y^x<0
o if x=y=-1, y^x=-1 < 0
o if x=3 and y=-1, y^x=-1 < 0

INSUFF

(1) & (2)
From (2), y must be negative.
From (1), since y is negative, x must be a positive number such that x+y > 0

Thus, x > 0 > y

SUFF
User avatar
Matrix02
User avatar
Joined: 13 Sep 2006
Last visit: 03 Jul 2007
Posts: 143
Own Kudos:
55
Location: New York
Posts: 143
Kudos: 55
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 08:31
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Fig
(C) as well :)

Stat 1 : x+y >0
o if x=y=1, x+y=2 > 0
o if x=2 and y=1, x+y=3 > 0

INSUFF

Stat 1 : y^x<0
o if x=y=-1, y^x=-1 < 0
o if x=3 and y=-1, y^x=-1 < 0

INSUFF

(1) & (2)
From (2), y must be negative.
From (1), since y is negative, x must be a positive number such that x+y > 0

Thus, x > 0 > y

SUFF
Show more


I think is should be C. Please let me know if my logic is flawed for my analysis of Statement 2.

1) X+Y>0
2) y^x<0

Statement 1 is clearly not sufficient. x&y could both be positve or one could be positve and the other negative (either x could be pos/neg or y pos/neg - doesn't matter as result will be the same).

Statement 2: has various options to make y^x<0

Option 1: y=negative and x = positve odd integer
-3^5

Option 2: y=negative and x=negative
-3^-5

Combining Statement 1 & 2 we know one number is positive the other is negative. From statment 2 tells us y is negative and x is positive. Both statement are needed.

This one is tricky. I originally thought the answer was E. But in replying to this post I figure it our :wink: I think
User avatar
Fig
User avatar
Joined: 01 May 2006
Last visit: 02 Feb 2025
Posts: 1,031
Own Kudos:
253
Posts: 1,031
Kudos: 253
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 08:39
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Matrix02
Fig
(C) as well :)

Stat 1 : x+y >0
o if x=y=1, x+y=2 > 0
o if x=2 and y=1, x+y=3 > 0

INSUFF

Stat 1 : y^x<0
o if x=y=-1, y^x=-1 < 0
o if x=3 and y=-1, y^x=-1 < 0

INSUFF

(1) & (2)
From (2), y must be negative.
From (1), since y is negative, x must be a positive number such that x+y > 0

Thus, x > 0 > y

SUFF

I think is should be C. Please let me know if my logic is flawed for my analysis of Statement 2.

1) X+Y>0
2) y^x<0

Statement 1 is clearly not sufficient. x&y could both be positve or one could be positve and the other negative (either x could be pos/neg or y pos/neg - doesn't matter as result will be the same).

Statement 2: has various options to make y^x<0

Option 1: y=negative and x = positve odd integer
-3^5

Option 2: y=negative and x=negative
-3^-5

Combining Statement 1 & 2 we know one number is positive the other is negative. From statment 2 tells us y is negative and x is positive. Both statement are needed.

This one is tricky. I originally thought the answer was E. But in replying to this post I figure it our :wink: I think
Show more


Yes... :) Your way is good :) U prove that, either x > y or y > x, the statment remains true :) Thus, it's insufficient :)
User avatar
londonluddite
User avatar
Joined: 30 Aug 2006
Last visit: 28 Jan 2008
Posts: 221
Own Kudos:
286
Posts: 221
Kudos: 286
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 12:45
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Agree C,

I) x > -y INSUFF, x could be 2 and y could be 5
II) y^x < 0, y must be -ve INSUFF

using both x > -(-y), x > +y SUFF
User avatar
yezz
User avatar
Retired Moderator
Joined: 05 Jul 2006
Last visit: 26 Apr 2022
Posts: 833
Own Kudos:
1,661
Given Kudos: 49
Posts: 833
Kudos: 1,661
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 13:04
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Is X>Y ?

1) X+Y>0
2) y^x<0

x+y>0....insuff

x could be -ve and y +ve and /y/>/x/

or x+ve and y -ve and /x/>/y/

or both positive

y^x<0 ie x +ve or -ve odd number and y is a -ve number.........insuff

both together

x+ve and y -ve and /x/>/y/

thus suff

My answer is C ( X>Y)
User avatar
anandsebastin
User avatar
Joined: 23 Jun 2005
Last visit: 20 Jul 2011
Posts: 339
Own Kudos:
356
Given Kudos: 1
GMAT 1: 740 Q48 V42
GMAT 1: 740 Q48 V42
Posts: 339
Kudos: 356
Is X>Y ? 1) X+Y>0 2) y^x<0 13 Oct 2006, 20:49
Kudos
Add Kudos
Bookmarks
Bookmark this Post
[quote="kaitibruck"]Is X>Y ?

1) X+Y>0
2) y^x0 and y0
and x>y SUFF



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderators:
Bunuel
Math Expert
105390 posts
GMATBusters
GMAT Tutor
1924 posts