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Is x > y? (1) x= y+2 (2) x/2 = y-1

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Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 02 Jul 2012, 01:39
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The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Is x > y?

(1) x = y+2
(2) x/2 = y-1

Diagnostic Test
Question: 37
Page: 25
Difficulty: 550


GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

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Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 02 Jul 2012, 01:39
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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 02 Jul 2012, 01:44
Hi,

Difficulty level: 600

Using (1),
x = y + 2, so for any value of y, x > y. Sufficient.

Using (2),
x/2 = y - 1
for x = 0, y = 1 or x < y
for x = 2, y = 2 or x = y
for x = 4, y = 3 or x > y, Thus the relationship depends on value of x & y. Insufficient.

Thus, Answer is (A)

Regards,

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 02 Jul 2012, 11:28
1) Sufficient . X is always 2 greater than Y. (+,-ve and fraction).
2) Insufficient. For y=5, x = 8 so x> y but for y=-5, x= -12 so y> x..

A)

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 03 Jul 2012, 08:53
(1) x = y+2 sufficient .try zero, negative, positive integers and non-integers, and u will get answer YES, x>y.
(2) x/2 = y-1 means x=2(y-1) if y=1 x =0 so, the answ is No, but if y=3 x=4 the answer is Yes
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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 03 Jul 2012, 12:42
Is x > y?

(1) x = y+2
Regardless of whether y is a positive or negative, if x=y+2, then y is greater than x. SUFFICIENT.
(2) x/2 = y-1
This kind of logic pops up frequently from the GMAT probelms I have done.
x=2(y-1)
x=2y-2
Whenever you see mult/div AND sub/add on the other side of x, you won't be able to tell whether whether one integer is greater than the other. It could be either of the case.

Answer: A

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 21 Nov 2015, 09:18
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is x > y?

(1) x = y+2
(2) x/2 = y-1

We get x-y>0? when we modify the questions.
For condition 1, x-y=2>0 This is a 'yes', and sufficient.
For condition 2, x=2y-2, x-y=y-2. We cannot determine the sign of x-y, so this is insufficient.
The answer (A).

For (C), x=y+2, x=2y-2 --> y=2, x=4. This is insufficient as it is too trivial.

Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 13 Dec 2017, 20:25
Hi All,

We're asked if X is greater than Y. This is a YES/NO question. We can solve it by TESTing VALUES.

1) X = Y +2

With this Fact, we can see that X is "2 greater" than Y, so the answer to the question is ALWAYS YES. You can see this pattern with a few TESTs:
IF....
Y = 0, X = 2
Y = 5, X = 7
Y = -3, X = -1
Etc.
Fact 1 is SUFFICIENT

2) X/2 = Y - 1

IF....
Y = 1, X = 0 and the answer to the question is NO
Y = 3, X = 4 and the answer to the question is YES
Fact 2 is INSUFFICIENT

Final Answer:
[Reveal] Spoiler:
A


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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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New post 13 Dec 2017, 20:48
stmt 1: x= y +2 => x-y = 2 => x-y >0 => x > y (sufficient)
stmt 2: x/2 = y-1 => x = 2y -2 => x- 2y <0 => x< 2y (not sufficient)

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1   [#permalink] 13 Dec 2017, 20:48
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