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# Is x > y? (1) x= y+2 (2) x/2 = y-1

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Math Expert
Joined: 02 Sep 2009
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Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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02 Jul 2012, 01:39
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Difficulty:

25% (medium)

Question Stats:

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The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Is x > y?

(1) x = y+2
(2) x/2 = y-1

Diagnostic Test
Question: 37
Page: 25
Difficulty: 550

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Math Expert
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Kudos [?]: 139638 [0], given: 12794

Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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02 Jul 2012, 01:39
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SOLUTION

Is x > y?

(1) x = y+2. $$x$$ is 2 more than $$y$$, so $$x>y$$. Sufficient.

(2) x/2 = y-1 --> $$x=2y-2$$. If $$y=0$$ then $$x=-2$$ and the answer is NO but if $$y=3$$ then $$x=4$$ and the answer is YES. Not sufficient.

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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02 Jul 2012, 01:44
Hi,

Difficulty level: 600

Using (1),
x = y + 2, so for any value of y, x > y. Sufficient.

Using (2),
x/2 = y - 1
for x = 0, y = 1 or x < y
for x = 2, y = 2 or x = y
for x = 4, y = 3 or x > y, Thus the relationship depends on value of x & y. Insufficient.

Regards,

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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02 Jul 2012, 11:28
1) Sufficient . X is always 2 greater than Y. (+,-ve and fraction).
2) Insufficient. For y=5, x = 8 so x> y but for y=-5, x= -12 so y> x..

A)

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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03 Jul 2012, 08:53
(1) x = y+2 sufficient .try zero, negative, positive integers and non-integers, and u will get answer YES, x>y.
(2) x/2 = y-1 means x=2(y-1) if y=1 x =0 so, the answ is No, but if y=3 x=4 the answer is Yes
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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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03 Jul 2012, 12:42
Is x > y?

(1) x = y+2
Regardless of whether y is a positive or negative, if x=y+2, then y is greater than x. SUFFICIENT.
(2) x/2 = y-1
This kind of logic pops up frequently from the GMAT probelms I have done.
x=2(y-1)
x=2y-2
Whenever you see mult/div AND sub/add on the other side of x, you won't be able to tell whether whether one integer is greater than the other. It could be either of the case.

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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21 Nov 2015, 09:18
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

Is x > y?

(1) x = y+2
(2) x/2 = y-1

We get x-y>0? when we modify the questions.
For condition 1, x-y=2>0 This is a 'yes', and sufficient.
For condition 2, x=2y-2, x-y=y-2. We cannot determine the sign of x-y, so this is insufficient.

For (C), x=y+2, x=2y-2 --> y=2, x=4. This is insufficient as it is too trivial.

Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions.
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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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13 Dec 2017, 20:25
Hi All,

We're asked if X is greater than Y. This is a YES/NO question. We can solve it by TESTing VALUES.

1) X = Y +2

With this Fact, we can see that X is "2 greater" than Y, so the answer to the question is ALWAYS YES. You can see this pattern with a few TESTs:
IF....
Y = 0, X = 2
Y = 5, X = 7
Y = -3, X = -1
Etc.
Fact 1 is SUFFICIENT

2) X/2 = Y - 1

IF....
Y = 1, X = 0 and the answer to the question is NO
Y = 3, X = 4 and the answer to the question is YES
Fact 2 is INSUFFICIENT

[Reveal] Spoiler:
A

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1 [#permalink]

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13 Dec 2017, 20:48
stmt 1: x= y +2 => x-y = 2 => x-y >0 => x > y (sufficient)
stmt 2: x/2 = y-1 => x = 2y -2 => x- 2y <0 => x< 2y (not sufficient)

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Re: Is x > y? (1) x= y+2 (2) x/2 = y-1   [#permalink] 13 Dec 2017, 20:48
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