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Is x > y? (1) x/z > y/z (2) x > 0 > z

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Senior Manager
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Is x > y? (1) x/z > y/z (2) x > 0 > z  [#permalink]

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New post 26 Feb 2019, 08:07
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Is x > y?


(1) \(\frac{x}{z}\) > \(\frac{y}{z}\)

(2) x > 0 > z

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Re: Is x > y? (1) x/z > y/z (2) x > 0 > z  [#permalink]

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New post 26 Feb 2019, 23:30
Statement 1 :
If z > 0 , then YES
If z < 0 , then NO
Hence insufficient
Statement 2 :
Insufficient

Combined Sufficient
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Is x > y? (1) x/z > y/z (2) x > 0 > z  [#permalink]

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New post 27 Feb 2019, 06:14
This is how I did.
We need to find if x>y

Statement (1): \(\frac{x}{z}\) > \(\frac{y}{z}\)

Case I: If z>0, \(\frac{3}{1}\) > \(\frac{2}{1}\) => x>y (3>2)...yes
Case II: If z<0, \(\frac{3}{-1}\) > \(\frac{2}{-1}\) => x<y (-3<-2)...no

Variation in answers so INSUFFICIENT.

Statement (2): x > 0 > z Clearly INSUFFICIENT.

(1)+(2)= x>0 and z<0, and plugging in the numbers as per this range in \(\frac{x}{z}\) > \(\frac{y}{z}\) will always give x<y, which is clearly NO. Hence, combined statements are SUFFICIENT.
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Is x > y? (1) x/z > y/z (2) x > 0 > z   [#permalink] 27 Feb 2019, 06:14
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