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Is x < y ? (1) z + 1 < y (2) z > x

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Is x < y ? (1) z + 1 < y (2) z > x [#permalink]

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New post 30 Jan 2017, 10:49
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

80% (00:40) correct 20% (00:39) wrong based on 80 sessions

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Re: Is x < y ? (1) z + 1 < y (2) z > x [#permalink]

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New post 31 Jan 2017, 07:46
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Bunuel wrote:
Is x < y ?

(1) z + 1 < y
(2) z > x


(1) insuff ..no info on x
(2) insuff ..no info on y

combining
subtract both to get
1<y-x
1+x<y
thus x<y
suff

Ans C
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Is x < y ? (1) z + 1 < y (2) z > x [#permalink]

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New post 31 Jan 2017, 13:40
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Bunuel wrote:
Is x < y ?

(1) z + 1 < y
(2) z > x


Target question: Is x < y ?

Statement 1: z + 1 < y
Without any information about x, it's impossible answer the target question with certainty.
So, statement 1 is NOT SUFFICIENT

Statement 2: z > x
Without any information about y, it's impossible answer the target question with certainty.
So, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that z + 1 < y
Statement 2 tells us that x < z
To COMBINE these inequalities, recognize that z < z + 1
So, we can write: x < z < z + 1 < y
If we ignore the part in the middle, we can conclude that x < y
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer: C

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Re: Is x < y ? (1) z + 1 < y (2) z > x [#permalink]

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New post 10 Feb 2018, 06:51
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Re: Is x < y ? (1) z + 1 < y (2) z > x   [#permalink] 10 Feb 2018, 06:51
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