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rishi2377
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maratikus
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kanyshkae
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I am a bit puzzled with the above answers.The way I reasoned is as follows:

(1) Given x > y. Thus, |x|>|y| and |x|-|y|> 0. (*)
As well, x-y>0. so |x-y|>0 (**). However, it is difficult to clearly ascribe a relative magnitude to * and **. So, unclear.

(2) Given xy<0. This leads to two cases.
***x<0 and y>0. While x-y < 0, |x-y|>0.
****x>0 and y<0. In this case, x-y >0 and |x-y|>0.
However, again it is unclear, the relative magnitude between |x-y| and |x|-|y|. So, this is unclear as well.

So, the answer is E.
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pmenon
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i just picked numbers for B, and considered all 4 cases .... in each case, the LS was > RS ... so suff.
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neelesh
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kanyshkae
I am a bit puzzled with the above answers.The way I reasoned is as follows:

(1) Given x > y. Thus, |x|>|y| and |x|-|y|> 0. (*)

x = -2 , y = -5... while x > y but |x| < |y| ...
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rishi2377
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Thx mates.
OA is B ...guess what, this is a 720+ question on Prep. :p



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