Is x |y| y^2? (1) x y (2) y 0

Question

Is x·|y| > y^2?

(1) x > y

(2) y > 0

rpmodi · Answer

E .

1) x > y

x=-1 ; y=-3 ; x·|y| < y^2

x=3, y=2 ; x·|y| > y^2 , so insuff

2) y>0 , adding no information ,since we don't care about sign of y here , if it were given x>0 it would have been sufficient .

Together , no information about sign of x.

ldpedroso · Answer

I think it's C

If statement says Y>0, so of course x is a positive integer greater than Y, and thus, x·|y| > y^2.

gmatnub · Answer

The question is asking whether x is a positive number with a greater absolute value than y

statement 1: x > y, but if y is a negative, x can be a negative
insuff

statement 2: y > 0, x can be negative or x can be less than y
insuff

together
suff

C

FN · Answer

this is C..
even if X and y are fraction..

suppose x=1/2 and y=1/4

1/2*1/4=1/8>1/16

pmenon · Answer

i also get C

i worked with stat2 first ... since y>0, then we can rearrange for xy>y^2 --> y(x-y)>0, and so x-y must be greater than 0, i.e. x>y, but we dont know that. scratch B and D

from stat1, we just know x>y ... but nothing about the signs of each. insuff.

together, we know that x>y and that y is positive .... so therefore y(x-y) holds .

prasannar · Answer

C for me too.

stmt-1 x>y is not sufficient as this statement fails for y=0 and x,y -ve values

stmt -2 y>0 is not sufficient

combining both, we have y is +ve and thus x is +ve and thus C

rpmodi · Answer

Thanks guys for correcting my mistake !

Is x |y| > y^2? (1) x > y (2) y > 0

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